Where are the quadratic equations?
2x - 4 < 3x
Just follow the question.
Answer:
1: Reflect M across the x-axis
2: Dilate about the center by 3/2
Step-by-step explanation:
Given
See attachment for M and N
Required
Which maps M to N
The coordinates of the radius of the circles are:


And the radius of circles are:


The first transformation from M to M' is:
- Reflect across the x-axis
The rule is:


<em>At this point, M' and N now have the same center but different radius.</em>
The second transformation from M' to N is:
- Dilate about the center by dividing the radius of N by the radius of M
i.e.


<em>At this point, M has been completely mapped to N.</em>
Answer:
yes it will contain it
Step-by-step explanation:
.5 + 1.5 + .66 + .8 = 3.46