<span>7x - 5y =21
-7 -7
5y = 14
---- -----
5 5
y= 2.8
(4,2.8)</span>
It's the last answer. Think about when you move a point on a graph left 4 spaces it's on the x axis. Because it's going left it's going towards the negative numbers hence minus and not plus. some concept for the y axis.
Given:
In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.
To find:
The measure of angle P.
Solution:
According to the Law of Cosines:

Using Law of Cosines in triangle OPQ, we get




On further simplification, we get




Therefore, the measure of angle P is 79 degrees.
Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
Answer:
$11 Dollar
Step-by-step explanation:
35 - 24 = 11