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podryga [215]
3 years ago
9

Sam draws two polygons that are similar. The first polygon has a perimeter of 16 cm and the second polygon has a perimeter of 10

cm. Numerical Response If the shortest side of the first polygon has a length of 4 cm, then the corresponding side of the second polygon has a length of __________ cm.
Mathematics
1 answer:
Delvig [45]3 years ago
3 0
Scale: 10/16 = 5/8

solution: 5/8 x 4cm + 5/2cm = 2.5cm
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Marianna [84]
So, 10 x 10 is 100, x 8 is 800, your answer is D.

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8 0
4 years ago
Why is the lcm of two numbers never less than the larger number?
Lady bird [3.3K]
This involves a bit of logic in thinking about what LCM actually means.

LCM is the least common multiple. A common multiple is a multiple shared by two or more numbers. And by multiple, we mean some number multiplied by successive integers; this set contains multiples of 5 {5, 10, 15, 20, 25...}. You can see that the least (or lowest) common multiple is the lowest multiple shared by two numbers. Like for 6 and 9, you have {6, 12, 18, 24...} and {9, 18...}, so LCM(6,9) = 18. 

Now, if an LCM must be shared by both numbers, and to get a multiple of the largest number, you have to multiply by an integer greater than or equal to 1, then the LCM of two numbers can never be less than the larger of the twi numbers. Generally, if x and y are positive real numbers, and x is greater than y, LCM(x,y)  \leq x. 
4 0
4 years ago
Find x please show work if u can​
MAVERICK [17]

Answer:

x is 12

Step-by-step explanation:

You can find x two different ways.

The first way is to look at the numbers on the left side. You need to find the scale factor used to get from 4 to 6.

4 x 1.5 = 6

Use this for the 8

8 x 1.5 = 12

The other way you can use is look at the number on the top triangle. You need to find the scale factor used to get from 4 to 8.

4 x 2 = 8

Use this for the 6

6 x 2 = 12

7 0
3 years ago
Solve for all possible values of x.<br> Vx+7-11=2<br> Ox= 6<br> O x = 20<br> Ox= 162<br> Ox = 169
bixtya [17]
X=6. 6+7=13 13-11=2
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nika2105 [10]
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