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grandymaker [24]
3 years ago
10

Find the distance travelled in 1 h 40 min at a speed of 90 km/h

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0
90 km/h is your constant.
1h 40m - 1h since we have 90 km/h.
2/3 of 90 is what we need to find for the 40 min, since 40m/60m = 2/3.
60 is 2/3 of 90.
90 + 60 = 150.
Your distance traveled is 150km.
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A fish tank measures 20cm by 30cm by 40 cm. a jug holds 1.2 L. how many jugs of water are needed to fill the tank.
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Answer:

Multiply the numbers then divide by the amount of water in the jug

Step-by-step explanation:

6 0
3 years ago
Suzanne gets 7% commission on all of her sales. If she makes a sale of $350,000, how much commission will she make?
sasho [114]

Answer:

$24,500 of commission

Step-by-step explanation:

350000*0.07 = 24,500

4 0
2 years ago
Match the mathematical term with the correct definition.
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Convert the following to Standard Form: (x - 5)^2 + 4
netineya [11]

Answer:

x² - 10x + 29

Step-by-step explanation:

The standard form of a quadratic is , ax² + bx + c (a ≠ 0 )

Given

(x - 5)² + 4 ← expand factor using FOIL

= x² - 10x + 25 + 4

= x² - 10x + 29 ← in standard form

5 0
3 years ago
Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write
Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

  • Use double point formula and simplify it to get two eqaution.
  • Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1} (x - x1)

~ Keep all values.

(y  + 4) =  \frac{11 + 4}{2 + 1} (x + 1)

~ Simplify it.

y + 4 =  \frac{15}{3} (x + 1)

y + 4 = 5x + 5

5x - y + 1 = 0

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

(y - y1) =  \frac{y2 - y1}{x2 - x1}(x - x1)

~ Keep all values.

(y - 1) =  \frac{10 - 1}{4 - 1} (x - 1)

~ Simplify it.

y - 1 = 3 x - 3

3x - y - 2 = 0

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

m1 =  \frac{ - coeff. \: of \: x}{coeff \: of \: y}

m1 =  \frac{ - 5}{ - 1}

Therefore, m1 = 5

Slope of second equation.

m2 =  \frac{ - coeff \: .of \: x}{coeff \: .of \: y}

m2 =   \frac{ - 3}{ - 1}

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
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