Answer:
261∠36° Newtons
Step-by-step explanation:
A straightforward way to find the resultant is to add the x- and y-components of the forces:
r = 300(cos(-30°), sin(-30°)) +180(cos(45°), sin(45°)) +250(cos(135°), sin(135°))
= (300√3/2 +180√2/2 -250√2/2, -300/2 +180√2/2 +250√2/2)
= (150√3 -35√2, -150 +215√2)
≈ (210.310, 154.056)
≈ 260.698∠36.22°
The resultant is approximately 261 Newtons at an angle of 36°.
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From components (x, y), the angle is found as arctan(y/x). The magnitude is found as √(x²+y²).
The answer is 17 cents because first you have to multiply 23 hours by 60 minutes to get how many hours they worked which is 1,380 minutes, then you have to divide 247.25 by 1,380 which will get you how much they made per minute
Step-by-step explanation:
x=20
y=100
solution in image
The reason this is false is because the number you are subtracting with can be greater than the number your are subtracting from, resulting in a negative number. Or, if the order doesn't matter, the numbers can be the same. This results in a difference of 0, neither positive nor negative.
9514 1404 393
Answer:
a) 320 m
b) 4.838 seconds, or 11.162 seconds
Step-by-step explanation:
a) S(8) = -5(8^2) +80(8) = -320 +640 = 320
The height 8 seconds after takeoff will be 320 meters.
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b) S(t) = 270
270 = -5t^2 +80t
-54 = t^2 -16t . . . . . . divide by -5
10 = t^2 -16t +64 . . . . add 64
±√10 = t -8 . . . . . . . . . . take the square root
t = 8 ±√10 ≈ {4.838, 11.162}
The rocket will be at a height of 270 meters at 4.838 and 11.162 seconds after takeoff.
