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Anastaziya [24]
2 years ago
5

If -2x +7 = 3x - 8, then x =

Mathematics
1 answer:
Anna11 [10]2 years ago
6 0
-2x +7 = 3x - 8

Move the variable to the left-hand side and change its sign

-2x -3x+ 7 = -8

Move the constant to the right-hand side and change its sign

-2x -3x = -8 -7

Collect like terms

-5x = -15

Divide both sides of the equation by -5

x=3
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What is the value of the expression 2 over 2 plus 4 over 2 divide by 2 over 2
Lana71 [14]

Answer: I got 3.

Step-by-step explanation:

4 0
3 years ago
If it takes 3 days for 10 workers to finish building one house, how many days will it take 15 workers to finish four houses?
Ksivusya [100]
-- It takes 10 workers 3 days to build 1 house.
so
-- It takes 10 workers 1 day to build  1/3  of a house.
so
-- It takes 1 worker 1 day to build  1/30  of a house.

You got 15 workers and you need 4 houses ?

Well, as we just calculated . . .

-- It takes 1 worker 1 day to build  1/30  of a house.
so
-- It takes 15 workers 1 day to build  15/30 = 1/2  of a house.
so
-- It takes 15 workers 2 days to build 1 whole house.
so
-- It takes 15 workers  8 days  to build 4 houses.


8 0
2 years ago
357 is what percent of 510?
Mars2501 [29]

Answer:

70%

Step-by-step explanation:

357 = % of 510?

We know that 10% of 510 is 51 because 10% times 510. (0.1*510=51)

357 is divisible by 51.

357/51=7

357 is 7 10%s of 510.

357 is 70% of 510.

4 0
2 years ago
Which is the simplified form of the expression {(p^2)(q^50}^5 * {(p^-4)(q^50}^-2
ch4aika [34]
<span>{(p^2)(q^50}^5 * {(p^-4)(q^50}^-2
= </span><span>p^10 q^250 * p^8  q^-100
= p^18 q^150

Hope it helps.</span>
6 0
3 years ago
Read 2 more answers
Please help picture shown and show workkkk
tankabanditka [31]
1)
Area of largest circle - 2 * Area of one smaller circle = Area of the shaded region

AE = diameter of large circle = 48cm
radius of larger circle = diameter / 2 = 48cm / 2 = 24cm

4 circles fit across the diameter of the circle, so the diameter of the larger circle = 4 * diameter of the smaller circle
diameter of larger circle = 48cm = 4 * diameter of the smaller circle
diameter of the smaller circle = 48cm / 4 = 12cm
radius of smaller circle = diameter / 2 = 12cm / 2 = 6cm

Area of a circle = pi * r^2

Now plug the circle area equation into the first equation:
A_{shaded}=A_{l} - 2*A_{s}\\\\A_{shaded}=[\pi (r_{l})^{2}]-2*[\pi (r_{s})^{2}]\\\\A_{shaded}=[\pi (48cm)^{2}]-2*[\pi (6cm)^{2}]\\\\A_{shaded}=2304\pi-72\pi\\\\Area\ of\ shaded\ region\ is\ 2232\pi.


2)
Area of the shaded region = 2/7 * Area of the smaller circle
Area of the unshaded region = Area of larger circle + Area of smaller circle - Area of shaded region * 2
A_{unshaded}=[\pi (r_{1})^{2}]+[\pi (r_{2})^{2}]-2*[\pi (r_{2})^{2}]*\frac{2}{7}\\\\A_{unshaded}=[\pi (10cm)^{2}]+[\pi (7cm)^{2}] -\frac{4}{7}[\pi (7cm)^{2}]\\\\A_{unshaded}=100\pi\ cm^{2}+49\pi\ cm^{2}-\frac{4*49\pi\ cm^{2}}{7}\\\\A_{unshaded}=149\pi\ cm^{2}-(4*7*\pi\ cm^{2})\\\\A_{unshaded}=149\pi\ cm^{2}-28\pi\ cm^{2}\\\\\\A_{unshaded}=121\pi\ cm^{2}
3 0
3 years ago
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