Answer: I got 3.
Step-by-step explanation:
-- It takes 10 workers 3 days to build 1 house.
so
-- It takes 10 workers 1 day to build 1/3 of a house.
so
-- It takes 1 worker 1 day to build 1/30 of a house.
You got 15 workers and you need 4 houses ?
Well, as we just calculated . . .
-- It takes 1 worker 1 day to build 1/30 of a house.
so
-- It takes 15 workers 1 day to build 15/30 = 1/2 of a house.
so
-- It takes 15 workers 2 days to build 1 whole house.
so
-- It takes 15 workers 8 days to build 4 houses.
Answer:
70%
Step-by-step explanation:
357 = % of 510?
We know that 10% of 510 is 51 because 10% times 510. (0.1*510=51)
357 is divisible by 51.
357/51=7
357 is 7 10%s of 510.
357 is 70% of 510.
<span>{(p^2)(q^50}^5 * {(p^-4)(q^50}^-2
= </span><span>p^10 q^250 * p^8 q^-100
= p^18 q^150
Hope it helps.</span>
1)
Area of largest circle - 2 * Area of one smaller circle = Area of the shaded region
AE = diameter of large circle = 48cm
radius of larger circle = diameter / 2 = 48cm / 2 = 24cm
4 circles fit across the diameter of the circle, so the diameter of the larger circle = 4 * diameter of the smaller circle
diameter of larger circle = 48cm = 4 * diameter of the smaller circle
diameter of the smaller circle = 48cm / 4 = 12cm
radius of smaller circle = diameter / 2 = 12cm / 2 = 6cm
Area of a circle = pi * r^2
Now plug the circle area equation into the first equation:
![A_{shaded}=A_{l} - 2*A_{s}\\\\A_{shaded}=[\pi (r_{l})^{2}]-2*[\pi (r_{s})^{2}]\\\\A_{shaded}=[\pi (48cm)^{2}]-2*[\pi (6cm)^{2}]\\\\A_{shaded}=2304\pi-72\pi\\\\Area\ of\ shaded\ region\ is\ 2232\pi.](https://tex.z-dn.net/?f=A_%7Bshaded%7D%3DA_%7Bl%7D%20-%202%2AA_%7Bs%7D%5C%5C%5C%5CA_%7Bshaded%7D%3D%5B%5Cpi%20%28r_%7Bl%7D%29%5E%7B2%7D%5D-2%2A%5B%5Cpi%20%28r_%7Bs%7D%29%5E%7B2%7D%5D%5C%5C%5C%5CA_%7Bshaded%7D%3D%5B%5Cpi%20%2848cm%29%5E%7B2%7D%5D-2%2A%5B%5Cpi%20%286cm%29%5E%7B2%7D%5D%5C%5C%5C%5CA_%7Bshaded%7D%3D2304%5Cpi-72%5Cpi%5C%5C%5C%5CArea%5C%20of%5C%20shaded%5C%20region%5C%20is%5C%202232%5Cpi.)
2)
Area of the shaded region = 2/7 * Area of the smaller circle
Area of the unshaded region = Area of larger circle + Area of smaller circle - Area of shaded region * 2