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Jet001 [13]
3 years ago
8

Write an equation of the line pictured in the graph

Mathematics
1 answer:
8090 [49]3 years ago
3 0
Y=1/2x+2 s the answer

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Pleaseee help me will mark brainliest
ELEN [110]

We are going to define two equations where b means bagels and m will be muffins, First equation: 10*b + 4*m = 13 Second equation: 5*b + 8*m = 14 From the second equation, we can isolate b: b = (14 - 8*m)/5 In the second equation 10*(14 - 8*m)/5 + 4*m = 13 2*(14 - 8*m) + 4*m = 13 28 - 16*m + 4*m = 13 28 -13 = 16*m - 4*m 15 = 12*m m = 15/12 = 1.25 Then b = (14 - 8*m)/5 = (14 - 8*1.25)/5 = 4/5 = 0.8 So one bagel costs $0.8 and one muffin $1.25

6 0
3 years ago
Read 2 more answers
I GIVEEE BNRAINLILSTTT
taurus [48]

Answer:bfdbdfbdfvxcvdfbsdfbfdbdffdbbfdbf

7 0
3 years ago
Minimum Average Cost
Dahasolnce [82]

Answer:

a)\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

b)\bar{C}(x)=5.81

Step-by-step explanation:

Given that

C = 100 + 25 x - 120 ln x   ,x ≥ 1.

The average cost function given as

\bar{C}(x)=\dfrac{C(x)}{x}

\bar{C}(x)=\dfrac{100 + 25 x - 120 \ln x}{x}

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx{x}

Therefore

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

To find average minimum cost

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

\dfrac{d\bar{C}(x)}{dx} = -\dfrac{100}{x^2} +0-120\times \dfrac{1-lnx}{x^2}

0 = -\dfrac{100}{x^2} +0- 120\times \dfrac{1-lnx}{x^2}

100 + 120 (1-lnx) = 0

lnx=\dfrac{220}{120}

ln x =1.833

x=e^{1.833}

x=6.25

\bar{C}(x)=\dfrac{100}{6.25}+25-120\dfrac{ln6.25}{6.25}

\bar{C}(x)=5.81

6 0
4 years ago
HELP PLEASE HELP HELP
Luba_88 [7]

Answer:

10x² - 12

Step-by-step explanation:

4x² - 7 + 6x² - 5 (combine like terms)

10x² - 12

3 0
3 years ago
Read 2 more answers
Evaluate 3 over 2y-3 + 5 over 3z when y=6 and z=3.
anastassius [24]

Answer:

\frac{8}{9}Step-by-step explanation:[tex]\frac{3}{2y-3}  + \frac{5}{3z}    y = 6, z = 3

Substitute values into the expression:

\frac{3}{2(6)-3}  + \frac{5}{3(3)}

Simplify both fractions:

\frac{3}{9}  + \frac{5}{9}

Add the fractions:

[tex]\frac{8}{9}

3 0
4 years ago
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