Hi,
To find K you will pick a value from the x and then the corresponding Y value. Then we will plug it into the equation that is given y=Kx
Here:
X=25 Y=160
160=k25
(Divide both sides by 25 to isolate K)
K=6.5
Then plug K value into equation
Y=6.5X
Then if you want to check if that is correct you can pick a different point on the table and plug that into the equation to see if you get the same value.
Check:
X=50
Y=6.5x50
Y=320
Answer:
70 miles /hour = r
Step-by-step explanation:
d=rt
Substitute d=350 miles and t = 5 hours
350 miles = r* 5 hours
Divide each side by 5 hours
350 miles = 5 hours = r
70 miles /hour = r
Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.
From the table, the median position is calculated as:
The 0.2nd data falls in the 0.4 field goal category.
So, the median element is:
However, the distribution of the table are concentrated on the left.
This means that, the distribution is not uniform, instead it is skewed right.
A uniform distribution has a skewness of 0.
Hence, Fatima's claim is not supported by the table
Read more about distributions at:
brainly.com/question/13233983
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
Answer:
26
Step-by-step explanation:
just add 21 plus 5 then
