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Advocard [28]
3 years ago
15

Solve the system using the substitution method: 3x + 5y = -10 X - 5y =-10

Mathematics
1 answer:
inn [45]3 years ago
4 0

<u>Answer:</u>

Point Form:

(−5,1)

Equation Form:

x=−5, y=1

<u>Step-by-step explanation:</u>

Solve for the first variable in one of the equations, then substitute the result into the other equation.

1.  x=5y−10

2. 20y−30=−10

3. y=1

4. x=−5

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Find the 40th term in the arithmetic sequence: 4,2,0,-2........
navik [9.2K]

Answer:

-74

Step-by-step explanation:

6 0
3 years ago
If the scale factor between a scale drawing of a rectangle and the real object is 1:3 what would be the ratio of the areas?
Ivanshal [37]

Answer:

The ratio of the areas will be will be 1 : 9

Step-by-step explanation:

The linear scale factor represents a ratio that is used to multiply the dimensions of objects so that accurate geometries can be transferred between real-life and paper.

The linear scale factor is quite different from the area scale factor but related to it in the following way:

The area factor can be obtained by squaring the linear scale factor.

This is Area factor = (Linear scale factor) ^2.

Linear scale factor = (1:3)

Area factor = 1^2 : 3^2

Area factor will be 1: 9

Thus, when the linear scale factor is 1:3 the area factor will be 1 : 9

7 0
3 years ago
Answer the 3 screenshotted questions below. 30 points!
Triss [41]

Answer:

13.  36a^2b^4π  

14. 16x^3y^4π

15. -\frac{c^3}{4a^7b^3}

Step-by-step explanation:

13.

A = π * r^2

r = 6ab^2

A = π*  (6ab^2)^2

A = π * (6ab^2)(6ab^2)

A = π * 36a^2b^4

A = 36a^2b^4π  

14.

V = π * r^2 * h

r = 2x

h = 4xy^4

V = π * (2x)^2 * 4xy^4

V = π * 4x^2 * 4xy^4

V = π * 16x^3y^4

V = 16x^3y^4π

15. \frac{3a^{-4}b^2}{-12a^3b^5c^{-3}} = -\frac{c^3}{4a^7b^3}

\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}

\frac{a^{-4}}{-4a^3b^5c^{-3}}

\frac{b^2}{-4^{3+4}b^5c^{-3}}

\frac{b^2}{-4^7b^5c^{-3}}

\frac{1}{-4a^7b^{5-2}c^{-3}}

\frac{1}{-4a^7b^3c^{-3}}

\frac{c^3}{-4a^7b^3}

-\frac{c^3}{4a^7b^3}

Hope this helps!

3 0
3 years ago
a quantity with an initial valuve of 390 decays continuously at a rate of 5% per decade what is the value of the quantity after
pogonyaev

Answer:

4695.90

Step-by-step explanation:

The exponential growth function is given as:

y = a(1 + r)^t

a = Initial value = 390

y = Value after time t = ?

r = Growth rate = 5% = 0.05

t = Time in years =51

Hence

y = 390(1 + 0.05)⁵¹

y = 4695.9002123

Approximately = 4695.90

5 0
3 years ago
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