3 years ago

Jeep TrackPerimeter:15 ft40ft55 ft17 ft10 ft8 ft102 t

Mathematics

1 answer:

krek1111 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

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Use appropriate tools . How can you use a graph to determine that a relationship is not a function ?

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Answer:

by showing dots and correlations in a graph which will have an estimated slope, while not a definite one

Step-by-step explanation:

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3 years ago

Triangle IJK has the coordinates listed:

olga nikolaevna [1]

Point j’ is at (-10, -8)

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The radius of a circle measures 16 mm what is the circumference of the circle?

Zigmanuir [339]

The formula for the circumference of a circle is 3,14 (pi) x diameter. We know that the radius is half of the diameter so therefore you do 16x2= 32 —> 3,14x32= 100,48mm. Answer: 100.48mm

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3 years ago

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lora16 [44]

Answer:

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3 years ago

my hw write find an equation of the line passing through (-2,3) and (4,-5) I have to write the equation in slope-intercept form

Viefleur [7K]

Answer:

The line passing through the given points is:

$y=-\frac{4}{3}x+\frac{1}{3}$

in its slope-intercept form

Step-by-step explanation:

Start by finding the slope of the segment that joins the two given points using the slope formula:

$slope=\frac{y_2-y_1}{x_2-x_1}$

which for our case renders:

$slope=\frac{3-(-5)}{-2-4}=\frac{8}{-6} =-\frac{4}{3}$

Now we can find the y-intercept by using any one of the given points in the general slope-intercept form of a line with this slope:

$y=-\frac{4}{3} x+b\\3=-\frac{4}{3} (-2)+b\\3=\frac{8}{3}+b\\b=3-\frac{8}{3} \\b=\frac{9-8}{3} \\b=\frac{1}{3}$

Therefore, the equation of the line becomes:

$y=-\frac{4}{3}x+\frac{1}{3}$

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3 years ago

Jeep TrackPerimeter:15 ft40ft55 ft17 ft10 ft8 ft102 t​

Jeep TrackPerimeter:15 ft40ft55 ft17 ft10 ft8 ft102 t