<em>Answer:</em>
Thrust and Lift.
<em>Method:</em>
There are 4 forces acting upon a plane while it is moving. Drag (The air friction while it's in the air), Lift (Generated by the wings (The upward force), Weight (How heavy the plane is), and finally, Thrust (Generated by the engines which moves the plane/wings through the air generating lift). If there is enough air going over the wing at a high enough speed, and Thrust, and Lift overcome the other two forces keeping the plane on the ground, it can fly. The air pressure under the wing is higher than over the wing - If you have ever ran you hand under the water keeping it flat, you may notice it going up, those are basically the same forces, but under water.
How does the pressure under the wing affect the lift?
The difference of air pressure over the wing (which is less), which also means less force bringing the plane down. The air pressure under the wing is higher, putting pressure on the wing moving it up. A wing is designed to make the air travel a longer distance over the wing than under the wing creating the air pressure. The engines just enforce that process.
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Air pressure is caused by the air molecules around us. Air particles are always in random and continuos motion, bombarding each other in random direction. As air particles collide they create pressure.
Answer:
The wolf population greatly increases
Explanation:
Study island
Answer:
we will know that the allelic frequencies are for R 0.95 and r 0.05
Explanation:
We know that the population is in Hardy-Winberg equilibrium, we deduce the following formula:
p + q = 1
p2 + 2pq + q2 = 1
data
R: red flower allele
r: allele blor blanca
p would be equal to the allelic frequency R
q will be equal to the frequency allelic r
2p = RR
2q = rr
2pq = Rr
If there are 25 white flowers in 1000 plants, their frequency will be:
2pq frequency of the Rr genotype
white flower = 25/10000 = 0.0025 = rr = 2q = 0.0025
we deduce that q is equal to 0.05
we replace the data with the previous formula
p + q = 1
p = 1-0.05
we get as a result
p = 0.95
if p = 0.95 and q = 0.05
we will know that the allelic frequencies are for R 0.95 and r 0.05