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Svetllana [295]
3 years ago
13

Emelio wants to solve this equation.

Mathematics
2 answers:
Ludmilka [50]3 years ago
5 0

Answer:

Answer is 175

:)

Step-by-step explanation:

Kaylis [27]3 years ago
5 0

Answer:

What the guy said on top is correct.

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Can sum1 do this for me
Ierofanga [76]

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5 0
2 years ago
PLEASE HELP I HAVE 10 MORE MINUTES TO FINISH THIS!!!
evablogger [386]

Answer:

b

Step-by-step explanation:

add 5+3 then add 1/2 plus 3/4

7 0
3 years ago
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=74,000+80x
SOVA2 [1]

Answer:

a) $675000

b) $289000 profit,3300 set, $190 per set

c) 3225 set, $272687.5 profit, $192.5 per set

Step-by-step explanation:

a) Revenue R(x) = xp(x) = x(300 - x/30) = 300x - x²/30

The maximum revenue is at R'(x) =0

R'(x) = 300 - 2x/30 = 300 - x/15

But we need to compute R'(x) = 0:

300 - x/15 = 0

x/15 = 300

x = 4500

Also the second derivative of R(x) is given as:

R"(x) = -1/15 < 0 This means that the maximum revenue is at x = 4500. Hence:

R(4500) = 300 (4500) - (4500)²/30 = $675000  

B) Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 80x) = -x²/30 + 300x - 80x - 74000

P(x) = -x²/30 + 220x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 220= -x/15 + 220

But we need to compute P'(x) = 0:

-x/15 + 220 = 0

x/15 = 220

x = 3300

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3300. Hence:

P(3300) =  -(3300)²/30 + 220(3300) - 74000 = $289000  

The price for each set is:

p(3300) = 300 -3300/30 = $190 per set

c) The new cost is:

C(x) = 74000 + 80x + 5x = 74000 + 85x

Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 85x) = -x²/30 + 300x - 85x - 74000

P(x) = -x²/30 + 215x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 215= -x/15 + 215

But we need to compute P'(x) = 0:

-x/15 + 215 = 0

x/15 = 215

x = 3225

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3225. Hence:

P(3225) =  -(3225)²/30 + 215(3225) - 74000 = $272687.5

The money to be charge for each set is:

p(x) = 300 - 3225/30 = $192.5 per set

When taxed $5, the maximum profit is $272687.5

3 0
2 years ago
What happens to the value of the expression c+2 as c increases..please help
boyakko [2]

c+2 increases linearly with c. That means that if c increases by 1, c+2 will increase by 1; if by 2, c+2 will increase by 2; and so on.

y = c+2 is a "linear function of c."

5 0
3 years ago
Read 2 more answers
Can some one help me
matrenka [14]
So again, you want to convert to decimals. 3 13/20=3.65 an 92/25= 3.68
so in order of least to greatest, you have 3 13/20, 92/25, 3.78, 3.788
8 0
3 years ago
Read 2 more answers
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