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Virty [35]
4 years ago
12

What is 62500000 in standard form

Mathematics
1 answer:
8090 [49]4 years ago
5 0
<span>Not included first digit (6), there are 7 digits so 

62 500 000 = 6.25×10^7</span>
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Can someone help me find the value of x and the value of y? I need them to show their work, too.
solniwko [45]

\bf \begin{cases} x-2y=0\\ 2x-5y=-4 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ x-2y=0\implies x=2y \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting the found \underline{x} in the 2nd equation}}{2(2y)-5y=-4}\implies 4y-5y=-4\implies -y=-4 \\\\\\ y=\cfrac{-4}{-1}\implies \blacktriangleright y=4 \blacktriangleleft \\\\[-0.35em] ~\dotfill

\stackrel{\textit{substituting the found \underline{y} in the 1st equation}}{x-2(4)=0}\implies x-8=0\implies \blacktriangleright x=8 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (8,4)~\hfill

4 0
3 years ago
A sample of students that had stuffy or runny noses were blindly given a single Skittles candy to put in their mouth. They were
Korvikt [17]

Answer:

The confidence interval is  0.2857<  p <  0.4601

Step-by-step explanation:

From the question we are told that

  The sample size is  n  =  118  

   The  number that gave the correct answer is  k =  44

Generally the sample proportion is mathematically represented as

      \^ p = \frac{44}{118}

=>     \^ p =0.3729

Generally given that the confidence level is  95% the level of significance is mathematically represented as

       \alpha  =  (100 -95) \%

=>     \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{p(1 - p)}{n} }

=>   E =  1.96 * \sqrt{\frac{0.3729(1 - 0.3729)}{118} }

=>    E = 0.0872

Generally 95% confidence interval is mathematically represented as  

             \r p -E <  p <  \r p +E

=>    0.3729 -0.0872<  p <  0.3729 +0.0872

=>  0.2857<  p <  0.4601

5 0
3 years ago
Given the function with f(3) = 127 and f(1) = 95, determine the rate of change over the interval 1 &lt;3 &lt;3
Sonbull [250]

Answer:

When we have a function f(x) = y.

The rate of change between a and b (where a < b) is:

R = (f(b) - f(a))/(b - a)

In this case:

b = 3

a = 1

f(3) = 127

f(1) = 95

R = (127 - 95)/(3 - 1) = 16

The rate of change in that interval is 16.

3 0
4 years ago
The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
Fantom [35]

Answer:

108 ft²

Step-by-step explanation:

For the polygon on the left, we are given the length of one side (3 ft) and the total area (27 ft²). With this information, we can determine the length of the other side - 9 ft. I found this by dividing 27 ft² by 3 ft, giving me the final result of 9 ft.

Next, we have to find the other side of the polygon on the <em>right</em> so we can ultimately determine its area. It looks like there is a scale factor of 2 between the two polygons, since 3 × 2 = 6. We know that the bottom side of the left polygon is 9, so multiplying 9 by 2 should give us the bottom side of the polygon on the right. 9 × 2 = 18.

Now, we have the side lengths for the polygon on the right and can determine its area. What is 6 ft × 18 ft? Well, the answer is 107 ft², and this is the answer to the question.

Hopefully that's helpful! :)

5 0
2 years ago
CAN SOMEONE PLZ HELP
dybincka [34]
It would be C. 7*7*7*7*7

Hope this helps

Have a great day/night
8 0
3 years ago
Read 2 more answers
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