Etermine the x-intercept and y intercept of the following equations.

The graph shows the number of points, y, a player earns in a balloon game

Lilit [14]

Y = 25x
Slope is rise over run or (y2-y1)/(x2-x1)
(25-0)/(1-0)=25
No b value in y=mx+b because the origin is at 0.

8 0

2 years ago

PLS HELP ASAPPP plsss

Anna71 [15]

Answer:

27.5

Step-by-step explanation:

this is the trigonometric ratio.. we are looking for d... that is the opposite... any side facing the angel is the opposite.... so the longest side of the right angle triangle is the hypotenuse........ so you are looking for the opposite and you are giving the hypotenuse.... so the easiest way to know how to find it is by using this way...... SOH CAH TOA..... the first words stand for sin cosine and tangent of angles.... we are using sin.... because it says opposite / hypotenuse... and as you can see the angle which is 39 degree we will use sin 39.....what will be sin 39=d/30m....then ull cross multiply.... d=30m* sin 39.....

d = 30m *0.963

d = 28.8

but since 27.5 is dere....

you can round up to 1 sig. f =28

4 0

2 years ago

A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s

Artemon [7]

Answer:

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

$x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 0 \ \leq age \leq 2 }\\{0 \ \leq age \leq 3}\end{array}\right]$

Also , the age transition matrix is as follows:

$L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]$

After 1 year ; the age distribution vector will be :

$x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right] \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]$

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

6 0

2 years ago

What would be the value of $150 after eight years if you earn 12 percent interest per year? A. $371.39 B. $415.96 C. $465.88

salantis [7]

<h3>What would be the value of $150 after eight years if you earn 12 % interest per year? A. $371.39 B. $415.96 C. $465.88 </h3>

<em>The compound interest is applied, that is to say, each year the interest produced is accumulated to the outstanding capital and the interest of the next period is calculated on the new outstanding capital.</em>

The formula for calculating compound interest is:

Compound interest = Total amount of Principal and interest in future less Principal amount at present = [P(1 + i)ⁿ] – P

(Where P = Principal, i = nominal annual interest rate in percentage terms, and n = number of compounding periods)

[P(1 + i)ⁿ] – P = P[(1 + i)ⁿ – 1] = $150[(1 + 12/100)⁸ – 1] = $150[(1.12)⁸ – 1] = $150[2.47596317629 - 1] = $150[1.47596317629] = $221.39

Total amount = $150 + $221.39 = $371.39

Answer : A.) $371.39

$\textit{\textbf{Spymore}}$

5 0

3 years ago

How do i solve 6m_2=m+13

I am Lyosha [343]

If it's addition you do the opposite which is subtraction and that's the answer that you get so 6m_2=m+13 so add 6-2=4 and then 13-4=9

7 0

2 years ago