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DaniilM [7]
3 years ago
14

Etermine the x-intercept and y intercept of the following equations.

Mathematics
1 answer:
quester [9]3 years ago
8 0
It’s c uk what I mean it’s c cuzzz
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The sum of the two numbers is 40 and the difference is 6. What are the numbers?
natita [175]

Answer:

17 + 23 = 40

23 - 17 = 6 the other person did it right.

6 0
3 years ago
Read 2 more answers
Policeman A and Policeman B hand out 70 speeding tickets in a month.
Inessa05 [86]

Answer:

Policeman A = 56 tickets

Step-by-step explanation:

Policemen A + B = 70

If Policeman B hands out x no of tickets...

Then Policeman A hands out 4x no of tickets

meaning...

x + 4x = 70

5x = 70

x = 70/5

x = 14

Therefore Policeman A hands out..

4x = 4 × 14 = 56 tickets

8 0
3 years ago
Given the function f(x) = x2 and k = 3, which of the following represents the graph becoming more narrow? A. f(x)+k
Neko [114]
<span>The only type of transformation that can make a graph more narrow/wide is a scaling transformation. A scaling transformation involves a multiple factor. The answer to your question is B. </span>I hope that this is the answer that you were looking for and it has helped you.
4 0
3 years ago
Read 2 more answers
You can peel 48 potatoes in 10 minutes. How long will it take you to peel 100 potatoes?
dybincka [34]

Answer:

About 20.8 minutes

Step-by-step explanation:

TO solve this just think of it as a ratio. The number of potatoes goes on top and the time goes on bottom.

48

__

10

That is what the first one would look like. In the second one we know the number of potatoes but we are trying to find the time (x).

100

___

 x

Take these two ratios and set them equal to each other.

\frac{48}{10} =\frac{100}{x}      Next you cross multiply (take 48 times x and 100 times 10).

48x=1000    Now divide by 48 and you have your answer.

About 20.8 minutes

7 0
4 years ago
Suppose that $9500 is placed in an account that pays 8% interest compounded each year.
Blababa [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}


\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}

6 0
3 years ago
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