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gayaneshka [121]

2 years ago

5

Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form. 3 , 7 ,

11 ,

1 answer:

Tema [17]2 years ago

8 0

Answer: this is an arithmetic sequence and the common difference is equal to -4

Step-by-step explanation:

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nikdorinn [45]

Use the internet ok!!!!!!

4 0

3 years ago

Read 2 more answers

A pool is filled with 2,980 quarts of water. How many gallons of water are in the pool?.

Vladimir [108]

Answer:

B. 745 gallons

Step-by-step explanation:

<em><u>4 quarts = 1 gallon</u></em>

There are may ways to solve this, the easiest way is to divide the number of quarts by 4 (there are 4 quarts in a gallon).

2980 quarts /4 quarts = 745 gallons

8 0

2 years ago

Compare the rate at which each of the three students read.

laiz [17]

Answer:

here is the ANSWER-Connie : 1min = 200 words

Felicia : 1min = 260 words

Stew : 1 min = 265 words (8min = 2120 words, and 7min = 1855 words, so you minus 2120 - 1855 = 265 words)

STEW is the ANSWER

6 0

2 years ago

Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale

valkas [14]

Answer:

The specific weight is $1.5\frac{g}{cm^{3}}$

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

$LA=\pi rl$

we have

$LA=255\pi\ cm^{2}$

$l=17\ cm$

substitute the values

$255\pi=\pi r(17)$

Simplify

$255=r(17)$

$r=255/(17)=15\ cm$

step 2

Find the height of the cone

Applying the Pythagoras Theorem

$l^{2} =r^{2} +h^{2}$

substitute the values and solve for h

$17^{2} =15^{2} +h^{2}$

$h^{2}=17^{2}-15^{2}$

$h^{2}=64$

$h=8\ cm$

step 3

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

substitute the values

$V=\frac{1}{3}\pi (15)^{2}(8)$

$V=600\pi\ cm^{3}$

step 4

Find the specific weight

Divide the mass by the volume

$\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}$

4 0

2 years ago

PLEASE HELP ME WITH THIS!!!

kramer

I want to say the answer is 9

7 0

2 years ago