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3 years ago

HELP QUICKLY PLEASE HURRY!!!!!

Mathematics

2 answers:

BartSMP [9]3 years ago

6 0

Answer:

it looks to be c

Step-by-step explanation:

jok3333 [9.3K]3 years ago

6 0

The answer looks to be C

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Valentino's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is wha

trapecia [35]

Answer: Number of pizzas out of 4000 that is expected to be pan size

= 4000 * 168 / (326 + 309 + 247 + 168)

= 640

3 0

2 years ago

Slope -3; y intercept -4

levacccp [35]

Y=-3x-4 is the equation

6 0

3 years ago

Which ordered pair (c, d) is the solution to the given system of linear equations?

sasho [114]

Answer:

(-1,6)

Step-by-step explanation:

The missing part of this question is the system given as;

$-c+2d=13$

$-9c-4d=-15$

We solve for c in the top equation to get:

$c=2d-13$

Substitute $c=2d-13$ into the bottom equation to get:

$-9(2d-13)-4d=-15$

Expand to get:

$-18d+117-4d=-15$

Group similar terms to get:

$-18d-4d=-15-117$

$-22d=-132$

$d=6$

Put $d=6$ into $c=2d-13$ to get:

$c=2*6-13$

$c=12-13=-1$

The solution is (-1,6)

3 0

3 years ago

Read 2 more answers

Maggie's brother is 6 years younger than four times her age. The sum of their ages is 39. How old is Maggie?

poizon [28]

We can set Maggie's age to x

If her brother is six years younger than four times her age, than her brother must be equal to: 4x-6

Since the sum of their ages is 39, we can set up an equation.

(Sum of Maggie's age) + (sum of Maggie's brother's age) = 39

x + (4x -6) = 39

5x -6 = 39

5x = 45

x = 9 , Maggie's age is 9

6 0

3 years ago

Root 3 cosec140° - sec140°=4 prove that

Lorico [155]

Answer:

Step-by-step explanation:

We are to show that $\sqrt{3} cosec140^{0} - sec140^{0} = 4\\$

Proof:

From trigonometry identity;

$cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}$

$\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\$

From trigonometry, 2sinAcosA = Sin2A

$= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\= \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2 \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}$

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

$\frac{4(sin(420-140)) }{sin280}$

= $\frac{4sin280}{sin280}\\ = 4 \ Proved!$

3 0

3 years ago