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lbvjy [14]
3 years ago
14

The value of x in (3/4) raised to 6*(16/9) raised to 5 = (4/3) raised to 2 is-​

Mathematics
1 answer:
iragen [17]3 years ago
7 0

Answer:

The correct answer is 2.

Step-by-step explanation:

We simplify it until it reaches an answer that can no longer be simplified

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In the expression 7³ - 4 · 3 +8, the first operation is? A. An Exponent B. Subtraction C. Multiplication D. Addition
Vikki [24]

Answer:

An exponent

Step-by-step explanation:

look at PEM/DA/S

Parenthesis

EXPONENTS

and then you can stop the first operation is 7^3

this is an exponent

(also brainliest if this helped please!)

6 0
4 years ago
How do I even start?!
OlgaM077 [116]
For #1 you know that a straight line equalys 180 degrees so the look at the 3× degrees. 180-84 =96 /3= 32 degrees . x = 32
8 0
3 years ago
How many terms are there in the following expression? x - 5 + 16x + 4 - 2x - 3
k0ka [10]

Answer:

Two terms

Step-by-step explanation:

First, we have to simplify reducing the number of terms, since there are like terms

x-5+16x+4-2x-3

Eventually, you'll get 15x-4,  thus there are two terms.

Please correct me if I'm incorrect, and I'll change the answer, but I hope I helped :)

3 0
3 years ago
While on vacation in Canada, you notice that temperatures are reported in degrees Celsius. You know there is a linear
sashaice [31]

Since , the relation is linear .

Let equation is y = mx + c .

Putting , x = 0 and y = 32 .

32 = c  .......( 1 )

Also , putting x = 100 and y = 212 .

We get :

212 = 100m + c .......( 2 )

Comparing equation 1 and 2 .

100m = 212 - 32

x = 1.8

Therefore , y = 1.8x + 32 .

Hence , this is the required solution .

7 0
4 years ago
The distribution of the number of siblings for students at a large high school is skewed to the right with mean 1.8 siblings and
morpeh [17]

Answer:

E. Approximately normal with standard deviation less than 0.7 sibling

Step-by-step explanation:

To solve this question, we use the Central Limit theorem.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

Skewed right distribution, with \mu = 1.8, \sigma = 0.7

Sampling distribution of the sample mean for samples of size 100

By the Central Limit Theorem, they will be approximately normal, with mean \mu = 1.8, and standard deviation s = \frac{0.7}{\sqrt{100}} = 0.07

So the correct answer is:

E. Approximately normal with standard deviation less than 0.7 sibling

4 0
3 years ago
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