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3 years ago

7

A right rectangular pyramid is sliced parallel to the base, as shown What is the area of the resulting two-dimensional cross sec

tion? 15cm 18cm 25cm 50cm

1 answer:

omeli [17]3 years ago

8 0

Answer:

15 cm^2

Step-by-step explanation:

Simply multiply the base times the height of the cross section. So 3 x 5 is 15

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A Web music store offers two versions of a popular song. The size of the standard version is 2.1 megabytes (MB). The size of the

liq [111]

If the number of downloads of the standard version is x, and the high quality is x, 2.1*x+4.1*y=2761 (not 1010 due to that this is multiplied by 2.1 and 4.1, therefore representing the total amount of megabytes) In addition, there are 1010 total downloads, and it's either 2.1 MB or 4.1 MB, so x+y=1010.

We have
2.1x+4.1y=2761
x+y=1010

Multiplying the second equation by -2.1 and adding it to the first equation, we get 2y=2761-1010*2.1=640 and by dividing both sides by 2 we get y=320 downloads of the high quality version

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3 years ago

Look at the photo<br> answers are<br> radius <br> diameter<br> center<br> circumference

Dafna1 [17]

Answer:

Diamater= D

Radius= R

Center= C

Circumference= A

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3 years ago

The volume of water in a plastic bottle is 12.3 oz. Determine whether the data value is from a discrete or continuous data set.

Elena L [17]

Answer:

d

Step-by-step explanation:

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3 years ago

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a player gets to throw 4 darts at the target shown. Assuming the player will always hit the target, the probability of hitting a

padilas [110]

Answer:

3.375

Step-by-step explanation:

(3/5)^3 / (2/5)^3 = 3.375

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3 years ago

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A rectangle or piece of paper has a width is 3 inches less than its link it is cut in half along a diagonal to create two congru

kolezko [41]

The length and width of the rectangle is 11 in and 8 in respectively.

Step-by-step explanation:

Given,

The width of a rectangle is 3 in less than the length.

The area of each congruent right angle triangle = 44 in²

To find the length and width of the rectangle.

Formula

The area of a triangle with b base and h as height = $\frac{1}{2}$ bh

Now,

Let, the width = x and the length = x+3.

Here, for the triangle, width will be its base and length will be its height.

According to the problem,

$\frac{1}{2}$ ×(x+3)×x = 44

or, $x^{2} +3x = 88$

or, $x^{2} +3x-88 = 0$

or, $x^{2}$ +(11-8)x-88 = 0

or, $x^{2}$ +11x-8x-88 =0

or, x(x+11)-8(x+11) = 0

or, (x+11)(x-8) = 0

So, x = 8 ( x≠-11, the length or width could no be negative)

Hence,

Width = 8 in and length = 8+3 = 11 in

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3 years ago