Maybe if you need to measure a piece of clothing
Answer: P = 0
Explanation:
2x^2 + Px - 2 = 0
2x^2/2 + Px/2 - 2/2 = 0/2
x^2 + Px/2 - 1 = 0
If we plug P = 0
x^2 + 0x/2 - 1 = 0
x^2 + 0 - 1 = 0
x^2 - 1 = 0
(x - 1)(x + 1) = 0
Let's call the smaller number x:
y-x=5
xy=104
y-x=5 can be rewritten as y=x+5
Substituting this into the second equation gives:
x(x+5)=104
x^2+5x=104
x^2+5x-104=0
Then simply solve as a quadratic:
x^2+13x-8x-104=0
x(x+13) -8(x+13)=0
(x-8)(x+13) = 0
x=8,-13
the question said the numbers are positive, so x=8
if x=8,
y=x+5
y=13
So the two numbers are 8 and 13.
There’s gotta be an attachment
