The length of a rectangle is 2 m longer than its width. if the perimeter of the rectangle is 40 m , find its area.
1 answer:
L=w+2 and 2w+2l=40
Substitute length for w+2 in perimeter formula.
2w+2(w+2)=40
2w+2w+4=40
4w+4=40
4w=36
w=9
l=w+2
l=9+2
l=11
a=lw=11*9=99 meters
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