Answer:
1 / q^30.
Step-by-step explanation:
[(p^2)(q^5)]^-4 * [(p^-4)(q^5)]^-2
Using the law (a^b)^c = a^bc :-
= p^-8 * q^-20 * p^8 * q^-10
= p^(-8+8) * q^(-20-10)
= p^0 * q^-30
= 1 * q^-30.
= 1 / q^30.
Answer:$8.00
Step-by-step explanation:
Add them then u minus the $17.00
-4/3+1/3y I hope thats right
Domain is the set of x-values and range is the set of images f(x).
x F(x) = x + 7
-9 -9 + 7 = -2
-8 -8 + 7 = -1
-7 -7 + 7 = 0
-6 -6 + 7 = 1
-5 -5 + 7 = 2
-4 -4 + 7 = 3
-3 -3 + 7 = 4
So the range is {-2,4} <------ answer
