Ask question

Ask question

All categories

3 years ago

15

A recipe calls for 2 1/3 cups of flour and 1 1/4 cups of sugar. If the recipe is tripled, how much flour and sugar will be neede

d?

1 answer:

snow_tiger [21]3 years ago

6 0

2 1/3*3

7/3 *3

21/3

7 cups of flour

1 1/4

5/4*3

15/4

3 3/4 cups of sugar

You might be interested in

An animal shelter has 36 kittens and 12 puppies available for adoption. What is ration of puppies to kittens?

mestny [16]

The answer is 12:36 which reduces to 1:3

4 0

3 years ago

Read 2 more answers

What is 2.9 as a mixed number?

lapo4ka [179]

Answer:

2910 ….....................….......

3 0

3 years ago

Read 2 more answers

Please help, ill give brainliest, only if its right

alexira [117]

Answer:

it would be in the fourth quadrant, directly underneath where it is now. the base would be c and d

5 0

3 years ago

Look at the picture please help

morpeh [17]

Answer:

c

Step-by-step explanation:

First off, we know that (g ° f)(2) is just both functions done in a ordered fashion. In this case, f(x) is done first.

To figure out what f(2) is, all we have to do is find where x = 2 is on the graph. In this case it is on point (2, 3). The input is the x and the output is the y, so f(2) = 3.

Then, we can figure out what g(3) by locating x = 3 on line g. It shows the point (3, 0). This means that g(3) = 0.

3 0

2 years ago

Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.

Irina18 [472]

Answer:

<u>TO FIND :-</u>

Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

5 0

2 years ago