4 years ago

17h +1= [3h-7| for h.

Mathematics

1 answer:

OlgaM077 [116]4 years ago

6 0

Good evening

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Find the value of : <img src="https://tex.z-dn.net/?f=%20%5Csf%20log_%7B3%20%5Csqrt%7B2%7D%20%7D%28324%29%20" id="TexFormula1

qwelly [4]

Answer:

Step-by-step explanation:

Is that a log with the base of 3√(2) ?

If so....my calculator says the answer is 4

Let's see if we can do it w/ou the calculator:

3 sqrt(2)^x = 324 = 3^4 * 2^2 Now 'LOG' both sides:

x log (3 sqrt 2) = log (3^4 *2^2) = 4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)

now divide both sides by log (3 sqrt2 )

x = 4 (If I did the math correctly ! )

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Step-by-step explanation:

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3 years ago

A color printer prints 12 pages in 5 minutes. How many minutes does it take per page?

ElenaW [278]

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2.4

Step-by-step explanation:

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3 years ago

How many different 1-topping pizzas can be formed by choosing a size and topping if your choices for size are small, medium, lar

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3 years ago

Read 2 more answers

What is the average rate of change of the function

Reptile [31]

Answer:

Average rate of change $=-35.7084$

Step-by-step explanation:

Given function is $f(x)=480(0.3)^x$ and we need to find average rate of change of the function from $x=1\ to\ x=5$ .

Average rate of change $=\frac{f(b)-f(a)}{b-a}$

So,

$here\ b=5\ and\ a=1\\f(5)=480(0.3)^5\\=480\times0.00243=1.1664\\and\\f(1)=480(0.3)^1\\=480\times0.3=144$

Average rate of change

$=\frac{f(b)-f(a)}{b-a}\\\\=\frac{f(5)-f(1)}{5-1}\\\\=\frac{1.1664-144}{5-1}\\\\=\frac{-142.8336}{4}= -35.7084$

Hence, average rate of change of the function $f(x)=480(0.3)^x$ over the intervel $x=1\ to\ x=5$ is $=-35.7084$ .

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3 years ago