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Reika [66]
3 years ago
7

Please help me with question 19

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0
The answer is D- an investment of 80,000 dollars was needed and they invested a ration of 3:4 (3/4 or 75%), you round up to 80
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Rhianna has £25 to spend on plants.
frosja888 [35]

Answer:

£0.33

Step-by-step explanation:

Rhianna has £25.

1 plant costs £3.95, she buys all of them.

25/3.95 = 6.329114

She buys a total of 6 plants.

With £0.33 remaining, which is the change.

7 0
3 years ago
Read 2 more answers
I have no idea what the answers are
lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
Tammi deposited $520 into a bank account that earned simple interest each year. After 5 years, she had earned $156 in interest.
topjm [15]

Answer:

6%

Step-by-step explanation:

$156/5 years = $31.20 per year

$31.20/$520 = .06

.06 x 100 = 6%

6 0
3 years ago
A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
Over [174]

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

A survey of 35 people was conducted to compare their self-reported height to their actual height.

This means that n = 35

From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

t = 3.36

The test statistic is t = 3.36.

3 0
3 years ago
Please help asap i will mark branlist If correct
Alja [10]

Answer:

B is the only one that goes through the axis

3 0
3 years ago
Read 2 more answers
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