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4 years ago

Please help me with question 19

Mathematics

1 answer:

a_sh-v [17]4 years ago

8 0

The answer is D- an investment of 80,000 dollars was needed and they invested a ration of 3:4 (3/4 or 75%), you round up to 80

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Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on

Iteru [2.4K]

Answer:

$P(X_i=2) =\dfrac{1}{6}$

$P(X_i=-1) =\dfrac{5}{6}$

Step-by-step explanation:

Given the numbers on the chips = 1, 1, 3 and 5

Miguel chooses two chips.

Condition of winning: Both the chips are same i.e. 1 and 1 are chosen.

Miguel gets $2 on winning and loses $1 on getting different numbers.

To find:

Probability of winning $2 and losing $1 respectively.

Solution:

Here, we are given 4 numbers 1, 1, 3 and 5 out of which 2 numbers are to be chosen.

This is a simple selection problem.

The total number of ways of selecting r numbers from n is given as:

$_nC_r = \frac{n!}{r!(n-r)!}$

Here, n = 4 and r = 2.

So, total number of ways = $_4C_2 = \frac{4!}{2!\times 2!} = 6$

Total number of favorable cases in winning = choosing two 1's from two 1's i.e. $_2C_2 = \frac{2!}{2! 0! } = 1$

Now, let us have a look at the formula of probability of an event E:

$P(E) = \dfrac{\text{Number of favorable ways}}{\text{Total number of ways}}$

So, the probability of winning.

$P(X_i=2) =\dfrac{1}{6}$

Total number of favorable cases for -1: (6-1) = 5

So, probability of getting -1:

$P(X_i=-1) =\dfrac{5}{6}$

Please refer to the attached image for answer table.

7 0

3 years ago

School A rented and filled 5 vans and 9 buses with 499 students. School B rented and filled 10 vans and 9 buses with 539 student

V125BC [204]

Answer:

The Number of students:

A van can carry = x = 8 students

A bus can carry = y = 51 students

Step-by-step explanation:

Let us represent

Number of students:

A van can carry = x

A bus can carry = y

School A rented and filled 5 vans and 9 buses with 499 students.

5x + 9y = 499.... Equation 1

School B rented and filled 10 vans and 9 buses with 539 students.

10x + 9y = 539..... Equation 2

Combining both Equations

5x + 9y = 499.... Equation 1

10x + 9y = 539..... Equation 2

Using Elimination method

Subtract Equation 2 from 1

-5x = - 40

x = -40/-5

x = 8 students

Solving for y using Equation 1

5x + 9y = 499.... Equation 1

5 × 8 + 9y = 499

40 + 9y = 499

9y = 499 - 40

9y = 459

y = 459/9

y = 51 students

Therefore,

The Number of students:

A van can carry = x = 8 students

A bus can carry = y = 51 students

8 0

3 years ago

Which set of integers is ordered from least to greatest -13 , 4, 0, -8 -5 , -2, 3, 1 -12 , -18 , -4 , 7 -15, 6 , -9 , -21

HACTEHA [7]

Given:

The set of integers in the options.

-13 , 4, 0, -8

-5 , -2, 3, 1

-12 -18 , -4 , 7

-15, 6 , -9 , -21

To find:

The set of integers that is ordered from least to greatest.

Solution:

We know that the larger negative value is the smaller value and the larger positive value is the greater value.

Ordered from least to greatest means first we need to write the smallest value, write the value larger than and the greatest value occurs at the end.

In option A, we have -13 , 4, 0, -8. Here, 4>0. So, the option A is incorrect.

In option B, we have -5 , -2, 3, 1. Here, 3>1. So, the option B is incorrect.

In option C, we have -12 -18 , -4 , 7 Here, -12>-18. So, the option C is incorrect.

In option D, we have -15, 6 , -9 , -21. Here, 6>-9. So, the option D is incorrect.

Therefore, all the options are incorrect.

6 0

3 years ago

What is the shortcut to it ?

Virty [35]

Step-by-step explanation:

QP = QR (given by congruent marks)

SP = SR (given by congruent marks)

US is the common side

All 3 sides of each triangle are congruent with the other triangle.

Hence by SSS congruence,

triangles QPS and QRS are congruent.

7 0

3 years ago

35/48*100 fraction into percentage.

MA_775_DIABLO [31]

Answer:

729167

Step-by-step explanation:

Now we can see that our fraction is 72.916666666667/100, which means that 35/48 as a percentage is 72.9167%.

6 0

3 years ago