3^n=27
Solve Exponent.
3^n=27
log(3n)=log(27)(Take log of both sides)
n*(log(3))=log(27)
n=log(27) / log(3)
n=3
-3x + 5y = -9
4x + 8y = 12
Simplify the second,
x + 2y = 3
Times three,
3x + 6y = 9
Add to the first equation,
11y = 0
y = 0
-3x + 5(0) = -9
x = 3
Answer: x=3, y=0
Answer:
30 square inch
Step-by-step explanation:

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

which would be

in sigma notation.
To do this, notice that the denominator in each term is a power of 2, starting with
and ending with
. So in sigma notation, this series is
