Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
The muffins were done at 5:28
Step-by-step explanation:
you add 4:33 to 55 minutes knowing well that 60mins makes one hour
4:33
55
5:28
<u>Answer</u>:
c = 9
<u>Explanation</u>:
given: f(x)=3x-7
<em>if f(c) =20</em>
To solve this replace x with c and then y is 20.
<u>Solve</u>:
3c - 7 = 20
3c = 27
c = 27 ÷ 3
c = 9
You will end up with 8 bc if you cut it in half it is dividing so you would do 4×2 and the answer is 8