No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
Answer: y= 9x+ 25
Step-by-step explanation:
to calculate the slope, rise/run rise is difference in y-values 25 -(-2) =27
run is difference in x-values 0-(-3) = 3 . 27/3 = 9
b= y-intercept Given: 25
Answer:
-5
4x - 1 = 6x + 9
4x = 6x + 10
-2x = 10
x = -5