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VLD [36.1K]
3 years ago
9

The value of a collectible coin can be represented by the equation mc018-1.jpg, where x represents its age in years and y repres

ents its total value in dollars. What is the value of the coin after 19 years?
Mathematics
2 answers:
Scrat [10]3 years ago
6 0
The answer is $53

<span>x - age in years
y - total value in dollars
</span>
If the equation is y = 2x + 15, then after 19 years, the value will be:
x = 19

y = 2x + 15
y = 2 * 19 + 15
y = 38 + 15
y = 53
Nata [24]3 years ago
5 0

Answer:

the answer is $53, i just took the test

Step-by-step explanation:

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&lt;RQT is a straight angle. What are m&lt;RQS and m&lt;TQS​
never [62]

Answers:

  • x = 11
  • angle RQS = 106 degrees
  • angle SQT = 74 degrees

===========================================================

Explanation:

Straight angles are always 180 degrees in measure.

The two smaller angles shown add up to 180

(angle RQS) + (angle SQT) = angle RQT

(9x+7) + (6x+8) = 180

(9x+6x) + (7+8) = 180

15x+15 = 180

15x = 180-15

15x = 165

x = 165/15

x = 11

From here, we then know that,

  • angle RQS = 9x+7 = 9*11+7 = 99+7 = 106 degrees
  • angle SQT = 6x+8 = 6*11+8 = 66+8 = 74 degrees

Note how the two results add to 106+74 = 180 to help confirm the answers.

8 0
3 years ago
The absolute value of -2/3
Kruka [31]
2/3 is your answer to the question
4 0
3 years ago
Read 2 more answers
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
3 years ago
Please help.<br> Algebra.
Arlecino [84]

Answer:

Step-by-step explanation:

4)  C looks pretty good

5)  D looks great  

:)   ask if you'd like to know how I figured that out

6 0
3 years ago
Please help! its due today!!
nekit [7.7K]

Answer:

14

Step-by-step explanation:

a=1

b=2

d=2

c=10

K+L = 10¹+2² = 10+4 = 14

3 0
3 years ago
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