I just solved it and I'm pretty sure its only one solution, I took the bottom equation multiplied it by -3 then i canceled out the equations and got 9. So that would make it C.
Given:
In triangle ABC, AB = AC, AD is angle bisector and measure of angle C is 49 degrees.
To find:
The value of x and y.
Solution:
In triangle ABC,
(Given)
So, triangle ABC is an isosceles triangle and by the definition of base angles the base angles of isosceles triangle are congruent.
In isosceles triangle ABC,



The angle bisector of an isosceles triangle is the median and altitude of the triangle. So, the angle bisector is perpendicular to the base.


In triangle ABD,
[Angle sum property]
Therefore, the correct option is B.
SOLUTION
From the question, the center of the hyperbola is

a is the distance between the center to vertex, which is -1 or 1, and
c is the distance between the center to foci, which is -2 or 2.
b is given as
![\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Dc%5E2-a%5E2%20%5C%5C%20b%5E2%3D2%5E2-1%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
But equation of a hyperbola is given as

Substituting the values of a, b, h and k, we have
![\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%28x-0%29%5E2%7D%7B1%5E2%7D-%5Cfrac%7B%28y-0%29%5E2%7D%7B%5Csqrt%5B%5D%7B3%7D%5E2%7D%3D1%20%5C%5C%20%5Cfrac%7Bx%5E2%7D%7B1%7D-%5Cfrac%7By%5E2%7D%7B3%7D%3D1%20%5Cend%7Bgathered%7D)
Hence the answer is
Answer:
.15 * 60 = 9
$9
Step-by-step explanation: