How many tiles with dimensions 14 cm and 9 cm will be needed to fit in a rectangular

djverab [1.8K]

sara speed is half of Jeanette's so if jeanette ran 7 miles then her walking speed is 3.5MPH and sense she is 7 miles ahed sara is 10.5 miles behind... 3.5MPH which is jeanette speed is double than sara so 3.5/2 is 1.75MPH... Saras walking speed is 1.75MPH

5 0

3 years ago

a circular railroad-crossing sigh has a radius of 15 inches. which measurement is closest to the area of the sigh in square inch

S_A_V [24]

Answer:

30

Step-by-step explanation:

4 0

3 years ago

A tire manufacturer is considering a newly designed tread pattern for its all-weather tires. Tests have indicated that these tir

Nataly_w [17]

Answer:

With outlier (102)

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

$p_v =P(t_{9}>0.415)=0.344$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Without outlier (102)

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier, removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 129, 128, 130, 132, 135, 123, 102, 125, 128, 130

We can calculate the mean with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=126.2$ represent the sample mean

$s=9.138$ represent the sample standard deviation

n=10 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is significantly higher than 125, the system of hypothesis would be:

Null hypothesis: $\mu \leq 125$

Alternative hypothesis: $\mu > 125$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=10-1= 9$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{9}>0.415)=0.344$

Conclusion

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.

Using all the data we see that we don;t have enough info to conclude that the true mean is higher than 125, but if we see careful 9 of the 10 values are over the limit of 125 feet. And if we repeat the procedure with the outlier of 102. We got this:

$\bar X=128.89$ represent the sample mean

$s=3.551$ represent the sample standard deviation

$t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285$

First we need to calculate the degrees of freedom given by:

$df=n-1=9-1= 8$

Then since is a right tailed sided test the p value would be:

$p_v =P(t_{8}>3.285)=0.0056$

And we conclude that we reject the null hypothesis since $p_v$ . So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

8 0

3 years ago

A machine that fills 12-quart size packages of ice cream runs 8 hours a day, 7 days a week. The machine fills 900 ice cream pack

otez555 [7]

Answer:

Number of ice cream packaged each week = 604,800 Ice cream

Step-by-step explanation:

Given:

One package = 12 ice cream

Per day packing = 8 hour

Number of days work in a week = 7 days

Per hour packing = 900 package

Find:

Number of ice cream packaged each week :

Computation:

⇒ Number of ice cream packaged each week = Number of days work in a week × Per day packing hour × Per hour packing × Per package ice cream

⇒ Number of ice cream packaged each week = 7 × 8 × 900 × 12

⇒ Number of ice cream packaged each week = 604,800 Ice cream

8 0

3 years ago

HURRY ITS TIMED UUUUUUUUUUUUUUUUUYUUUUUUUUUYTDFBDHMHHDHKGFG

BabaBlast [244]

Answer:

3,2

Step-by-step explanation:

18,12

18/6 = 3

12/6 = 2

so

3,2

srry its timed so i tried to be quick

6 0

2 years ago

Read 2 more answers