Answer:42
Step-by-step explanation:
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, is equal to , thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, . Since a and b were generic elements of H, then H/G is abelian.
Answer:
Step-by-step explanation:
Solution is given below in attachment
Answer:
14.858
Step-by-step explanation:
16.058−1.2
=16.058−1.2
=16.058+−1.2
=14.858