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Anna11 [10]
3 years ago
15

Determine the number of electrons transferred in the balanced chemical equation. h2o

Chemistry
1 answer:
melomori [17]3 years ago
5 0
I think the answer to this question is three or 3
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Write the complete balanced equation for the following reaction: c7h14 o2 yields co2 h2o
Svetach [21]
C7H14 + 10.5 O2 -> 7 CO2 + 7 H2O

Or, if whole numbers must be used:

2 C7H14 + 21 O2 -> 14 CO2 + 7 H2O
3 0
3 years ago
Read 2 more answers
A 50.0 ml sample of 0.436 m nh4no3 is mixed with 200ml of 0.320 m nano3. what is the nitrate ion concentration in the resulting
igor_vitrenko [27]
Sorry idk. i was trying to figure it out but i cant
8 0
4 years ago
a man bought two watches for Rs 2500 each.He sold one of them at 10% . profit and the other at 4% loss.what was his gain or loss
timofeeve [1]

Answer:

Selling price of watch A and watch B= Rs. 425

Let cost price of watch A=x

Profit =10%

∴

100

110

x=425

x=386.36

Let cost price of watch B=y

Loss =10%

∴

100

90

y=425

y=472.22

Net cost price =x+y=858.5858

Net selling price =850

Loss%=

858.58

858.5858−850

×100=1%

Explanation:

please mark me as the brainliest answer and please please pleaseeee follow me for more answers to your questions

5 0
3 years ago
How many atoms are in 9.3moles of lithium?
vladimir1956 [14]

Answer:

3.45 moles Li  contains  2.08 × 10 (to the power of)24  atoms .

Explanation:

The relationship between atoms and moles is:

1  mole atoms =

6.022 × 10 (to the power of)23

atoms

In order to determine how many atoms occupy a given number of moles, multiply the given moles by  

6.022 × 10 (to the power of)23

atoms/mole

.

In the case of 3.45 moles lithium (Li):

3.45 mol Li × 6.022 × 10 (to the power of)23  atoms Li/ 1 mol Li =

2.08 × 10 (to the power of)24

atoms Li  rounded to three

3 0
3 years ago
Read 2 more answers
A balloon is filled with 500mL of helium at a temp of 27C and 75mmHg. What volume in mL will it have when it reaches an altitude
pickupchik [31]

Answer:

The answer to your question is: V = 60.3 ml

Explanation:

Data

V1 = 500 ml

T1 = 27°C = 300°K

P1 = 75 mmHg = 0.098 atm

V2 = ?

T2 = - 33°C = 240°K

P2 = 0.65 atm

Formula

                            \frac{P1V1}{T1}  = \frac{P2V2}{T2}

                            V2 = \frac{P1V1T2}{T1P2}

                            V2 = \frac{(0.098)(500)(240)}{(300)(0.65)} \

                            V2 = \frac{11769}{195}

                            V2 = 60.3 ml                        

5 0
3 years ago
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