Answer:
Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
i need points thanks for CO2moles
<span>Group 18: noble gases
This is a matter of memorizing the groups of the periodic table. The rightmost column is group 18 which is the noble gases: Helium, Neon, Argon, Krypton, Xenon, Radon. In general, the noble gases don't make chemical compounds. Although there have been some compounds made with the heavier noble gases (Krypton, Xenon, Radon).</span>
Answer:
The incorrect statement is "Most enzymes are proteins but some are lipids" the others statements are correct regarding to the Enzymes.
Explanation:
Enzymes are complex macromolecules of globular proteins. However, many enzymes contain certain non-protein substances associated with them for their function, which are known as cofactors and can be organic or inorganic compounds. In addition, the enzymes are thermolabile, presenting their best performance at the ideal temperature. Enzyme activity decreases with increasing and increases with increasing temperature and stops at 0 degrees and above 80 degrees. However, the enzymes of the bacteria that inhabit the hot springs have an ideal temperature of 70 degrees or more. Enzymes also show maximum activity at optimal pH. Varying its activity with increasing or decreasing pH. Enzymes are specific in their action. An enzyme can catalyze only a specific type of reaction or even act on a specific substrate. For example, the enzyme lactase catalyzes the hydrolysis of lactose and no other disaccharides.
Answer:
Final temperature of water is 83.8°C
Explanation:
In 500.0mL of a 6.00M NaOH solution, there are:
0.5000L × (6.00mol NaOH/ L) = <em>3.00moles of NaOH</em>
As the heat involved in dissolution is 44.5 kJ/mol, when the solution is dissolved:
44.5kJ/mol × 3.00moles = 133.5kJ = 133500J
Using coffee-cup calorimeter equation:
q = m×C×ΔT
<em>Where q is heat, m is mass of water (500.0g), C is specific heat of water (4.186J/g°C) and ΔT is change in temperature</em>
<em />
133500J = 500.0g×4.186J/g°C×(X-20.0°C)
63.8 = (X-20.0°C)
83.8°C = X
<em>Final temperature of water is 83.8°C</em>
