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natali 33 [55]
3 years ago
8

For the reaction 2Fe + O2 = 2FeO, how many grams of iron oxide are produced from 8.00 mol of iron? when o2 is an excess

Chemistry
1 answer:
Yanka [14]3 years ago
6 0

Answer:

The answer to your question is 576 grams of FeO

Explanation:

Balanced chemical reaction

                      2Fe  +  O₂  ⇒  2 FeO

       Reactant             Elements         Products

             2                         Fe                     2

             2                         O                       2

Data

mass of FeO = ?

moles of Fe = 8

Excess Oxygen

Process

1.- Convert moles of Fe to grams

Atomic mass = 56 g

                         56 g of Fe ------------------ 1 mol

                           x               ------------------ 8 moles

                           x = (8 x 56) / 1

                           x = 448 g of Fe

2.- Use the coefficients of the balanced reaction to find the grams of FeO.

Molecular mass of FeO = 2[ 56 + 16]

                                       = 144 g

               2(56) g of Fe ----------------------- 144 g of FeO

               448 g             -----------------------  x

                x = (448 x 144) / 2(56)

                x = 64512 / 112

               x = 576 grams of FeO

                       

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In ironmaking, iron metal can be separated from iron ore (Fe2O3) by heating the ore in a blast furnace in the presence of coke,
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The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.

<h3>Stoichiometric problem</h3>

From the equation of the reaction:

2 Fe_2O_3(s) + 3 C(s) --- > 4 Fe(s) + 3 CO_2(g)

The mole ratio of iron ore to carbon is 2:3.

Mole of 1000 kg of iron ore = 1000000/159.69

                                          = 6,262 moles

Mole of 120 kg carbon = 120000/12

                                 = 10,000 moles

Thus, it appears that the carbon is in excess while the iron ore is limited in availability.

The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:

              6,262 x 2 = 12,524 moles

Mass of 12,524 moles of iron = 12,524 x 56

                                                = 701,344 g or 701.344 kg

Thus, the theoretical yield of iron is 701.344 kg.

The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:

         6,262 x 3/2 = 9,393 moles

Mass of 9,393 moles carbon dioxide = 9,393 x 44

                                                         = 413,292 or 413.292 kg

The theoretical yield of carbon dioxide is, therefore, 413.292 kg.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

       

3 0
1 year ago
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