Answer: Q=1/2p+15,= p=2q-30= Slope = 1.000/2.000 = 0.500
p-intercept = -30/1 = -30.00000
q-intercept = 30/2 = 15
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
p-(2*q-30)=0
Solve p-2q+30 = 0
we have an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line p-2q+30 = 0 and calculate its properties
Notice that when p = 0 the value of q is 15/1 so this line "cuts" the q axis at q=15.00000
q-intercept = 30/2 = 15
When q = 0 the value of p is -30/1 Our line therefore "cuts" the p axis at p=-30.00000
p-intercept = -30/1 = -30.00000
Slope is defined as the change in q divided by the change in p. We note that for p=0, the value of q is 15.000 and for p=2.000, the value of q is 16.000. So, for a change of 2.000 in p (The change in p is sometimes referred to as "RUN") we get a change of 16.000 - 15.000 = 1.000 in q. (The change in q is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)
Slope = 1.000/2.000 = 0.500
9/3x = 5/8
Using the reciprocal, multiply each side by 3/9.
5/8 * 3/9 = 15/72
Simplify it : 5/24
x = 5/24
Hope this helps :)
0.89
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Answer:
The answer is "Option C".
Step-by-step explanation:
The graph of the even function will have both ends pointed in the same direction, while the graph of the odd function will have both ends pointed inside the reverse way. Furthermore, as the y-axis approaches, and also regular expression graph becomes symmetric. The graph of an unusual function, on either hand, is symmetric around the origin and also has rotational symmetry around the origin. They could see that the graph of function g meets a function requirement by looking at it. That graph of function f, but on the other hand, is not symmetric about its y-axis, implying that function f is not even. As both a result, g is a function that is even.
