Answer:
When the machine indicates a lie, what is the probability that the suspect is really lying? If the machine does not indicate a lie, what is the probability that the suspect is really telling the truth?
My solution if the probability that a test subject is chosen at random from the 200 in fact lie = 80/(80+5)=0.94
Then when 15% of people arrested lie, the probability that the suspect is really lying is 0.15*0.94=0.141
Step-by-step explanation:
Answer:
-3 = 4x -7
4 = 4x
1 = x
Step-by-step explanation:
hope this helps
Ok, let's use N and N'.
N is (-1,-1). N' is (4,6).
From point N, the quadrilateral moves to the right 5 and up 7.
So, N+(5,7)=N'.
