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mariarad [96]
3 years ago
9

Based on simple interest, find the total amount saved or owed. principal = $1056; rate = 3.75%; time = 6 years A. $1293.60 B. $1

452.00 C. $1689.00 D. $3432.00
Mathematics
1 answer:
Zarrin [17]3 years ago
4 0
The answer is A. 1293.60
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Events A and B have probabilities such that P(A) = 0.3, P(B) = 0.25, P(M ∪ N) = 0.425, and P(M ∩ N) = 0.075. Are events A and ev
nekit [7.7K]

Answer:

(C)Yes, because P(M) ∙ P(N) = P(M ∩ N)

Step-by-step explanation:

Two events A and B are independent if P(A)P(B)=P(A ∩ B)

Given events A and B such that:

P(A) = 0.3, P(B) = 0.25, P(A ∪ B) = 0.425, and P(A ∩ B) = 0.075

  • P(A)P(B)=0.3 X 0.25 =0.075
  • P(A ∩ B) = 0.075

Since the two expression above gives the same answer, they are independent.

<u>The correct option is C.</u>

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Find the greatest number of children to whom 260 pens and 364 chocolates can be divided equally.
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answer:

52

explanation:

52 is the highest shared factor of the two numbers.

52*5=260

52*7=364

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How long will it take an emperor penguin to swim 21 miles if it is swimming 7 mph?
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Researchers interviewed street prostitutes in Canada and the United States. The mean age of the 100 Canadian prostitutes upon en
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Answer:

Step-by-step explanation:

The null and the alternative hypothesis is:

H_o: \mu_c \ge \mu_{us}

H_a : \mu_c < \mu_{us}

The t- student test statistics can be computed as:

t = \dfrac{x_c- x_{us}}{\sqrt{\dfrac{\sigma_c^2}{n_c} + \dfrac{\sigma_{us}^2}{n_{us}} }}

t = \dfrac{19- 21}{\sqrt{\dfrac{7^2}{100} + \dfrac{8^2}{130} }}

t = -2.017  

degree of freedom = (n₁ - 1) + (n₂ - 1)  

= (100 - 1) + (130 - 1)

= 228

Using the data of t-value and degree of freedom;  

The P-value = -0.224

Decision rule: Do not reject the null hypothesis if the p-value is greater than ∝(0.01)

Conclusion: We reject the null hypothesis since the p-value is less than ∝.

Therefore, there is enough evidence to conclude that the mean age of entering prostitution in Canada is lower than that of the United States.

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