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Ulleksa [173]
3 years ago
13

Which transformations map the strip onto itself?

Mathematics
1 answer:
Pie3 years ago
4 0

Answer:

<h2>A horizontal translation and a 180° rotation only.</h2>

Step-by-step explanation:

Notice those shapes are positioned as a reflection.

So, one way to map them onto is self is by rotating 180° and a horizontal translation. Or it could work if we translate it horizontally, the we reflect it vertically. Those transformations would map the strip onto itself.

Therefore, the second choice is the best answer.

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The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
PLEASE HELP! all u have to do is determine whether it is positive or negative!!!
Sever21 [200]

Answer:

positive

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help find perimeter and area
klio [65]

Answer: perimeter = 96mm, Area = 564mm².

Step-by-step explanation:

From the diagram, it is a trapezium, it has a rectangle joined together by a right angled triangle. Now to find the perimeter, we add all the dimensions together. To get the other side of the rectangle, which is also the perpendicular height of the figure, we take the Pythagoras. Let the perpendicular height = x

Therefore,

25² = ײ + 7²

625 = x² + 49

x² = 625 - 49

x² = 576

x. = √576

= 24.

Now the perimeter

= 20 + 25 + 7 + 20 + 24

= 96mm.

Area of the figure will be

= 1/2( a + b )h

Where a = 20, b = 20 + 7 = 27 and h = 24, now substitute for the values

( 20 + 27) x 24

---------------------

2

= 47 x 24/2

= 47 x 12

= 564mm²

8 0
3 years ago
Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50
VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Let:</em>

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

\texttt{ }

<em>Jaces songs were played on 6 more commercials than movies.</em>

\boxed{C = 6 + M} → <em>Equation 1</em>

\texttt{ }

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

\boxed{50C + 140M = 680} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1  ↔ Equation 2 :</em>

50C + 140M = 680

50 ( 6 + M ) + 140M = 680

300 + 50M + 140M = 680

190M = 680 - 300

190M = 380

M = 380 \div 190

M = 2

\texttt{ }

C = 6 + M

C = 6 + 2

C = 8

\texttt{ }

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

5 0
3 years ago
Write an equivalent unit rate to eating 3 pieces of popcorn in of a minute.
Leviafan [203]

Answer:

180

Step-by-step explanation:

all I did was multiply

i don’t know  hope this is correct if not let me know so I can fix my mistake

5 0
3 years ago
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