i believe the answer is hours.
Here L = W, but H can be different.
The sum L+H+W must be less than or equal to 192 cm.
We can solve L + H + W = 192 for H: H = 192 - W - L. Remembering that W = L, the formula for H becomes 192 - 2W.
The formula for volume would be V = L*W*H.
This becomes V = W*W*H, or V = W^2*(192-2W)
Multiplying this out: V = w^2*192 - 2W^3
Two ways of determining W:
1) graph V = 192W^2 - 2W^3 and determine the value of W at which V is at a max with the constraint W + L + H is equal to or smaller than 192.
2) Differentiate V with respect to W and set the result equal to zero:
384W - 6W^2 = 0. Solving for W: W(384 - 6W) = 0.
W = 0 is trivial, so just solve 384 - 6W = 0 for W: 6W = 384, and W = 64.
The width is 64 cm, the length is 64 cm also, and the height is (192-2W) cm, or 64 cm.
These dimensions produce the max volume.
Answer:
The value of a and b are 8 and 1 respectively
Step-by-step explanation:
Conditional pdf of
Normalizing pdf of 1
We are given that PDF is of the form
So, on comparing 8x with
So, a = 8 , b = 1
So, the value of a and b are 8 and 1 respectively
Answer: new Q = (-4, 5)
<u>Step-by-step explanation:</u>
Given: Q = (-4, 1)
Reflected across y = -2:
Q is 3 units above y = -2 so a reflection is 3 units below y = -2 --> Q' = (-4, -5)
Reflected across x-axis:
Q' is 5 units below x-axis so a reflection is 5 units above x-axis --> Q'' = (-4, 5)
Yes.. exactly what the question says.. the graph has a line at bottom then 2 poles a right and left.. you measure from the straight line across to the point A at left pole.
~Hope This Helps~