So first of all you would add the two together
so it would be m23.
138÷23 would equal 6,
therefore m would equal six
to check it substitute m for 6 and you should get 138!
Angle a is congurent to angle e, so 60+8x=108
same with c and g.
so 8y-3x=62
just plug in x for there (6)
so 8y-24=62
then 8y=88
y=11
<h3>
Answer: Choice D. 4x^2 + 20x + 25</h3>
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Explanation:
Perfect square trinomials are in the form (a+b)^2 = a^2+2ab+b^2
So the first and last terms must be perfect squares. The middle term is twice that of the square roots of each first and last term.
Choice D fits the description because 4x^2 = (2x)^2 is the first term, so a = 2x and 25 = 5^2 is the last term meaning b = 5. Note how 2ab = 2*2x*5 = 20x is the middle term.
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(a+b)^2 = a^2+2ab+b^2
(2x+5)^2 = (2x)^2+2*2x*5+5^2
(2x+5)^2 = 4x^2 + 20x + 25
Answer:
It has 2 i hope it's correct :)
Answer:
None (no solutions)
Step-by-step explanation:
-10q=-10q-7 (add 10q to both sides to get the costant 7 by itself)
-10q+10q=-10q+10q-7
0=-7 ( zero will never equal -7 hence there are no solutions to this equation)
