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77julia77 [94]
3 years ago
9

With your typical convenience store customer, there is a 0.23 probability of buying gasoline. The probability of buying grocerie

s is 0.76 and the conditional probability of buying groceries given that they buy gasoline is 0.85. a. Find the probability that a typical customer buys both gasoline and groceries. b. Find the probability that a typical customer buys gasoline or groceries. c. Find the conditional probability of buying gasoline given that the customer buys groceries. d. Find the conditional probability of buying groceries given that the customer did not buy gasoline. e. Are these two events (groceries, gasoline) mutually exclusive? f. Are these two events independent?
Mathematics
1 answer:
Trava [24]3 years ago
6 0

Answer:

a) P ( A & B ) = 0.1995

b) P (A U B ) = 0.7905

c) P (A/B) = 0.2625

d) P(B/A')  = 0.194805

e) NOT mutually exclusive

f) NOT Independent

Step-by-step explanation:

Declare Events:

- buying gasoline = Event A

- buying groceries = Event B

Given:

- P(A) = 0.23

- P(B) = 0.76

- P(B/A) = 0.85

Find:

- a. Find the probability that a typical customer buys both gasoline and groceries.

- b. Find the probability that a typical customer buys gasoline or groceries.

- c. Find the conditional probability of buying gasoline given that the customer buys groceries.

- d. Find the conditional probability of buying groceries given that the customer did not buy gasoline.

- e Are these two events (groceries, gasoline) mutually exclusive?

- f  Are these two events independent?

Solution:

- a) P ( A & B ) ?

                     P ( A & B ) = P(B/A) * P(A) = 0.85*0.23 = 0.1995

- b) P (A U B ) ?

                    P (A U B ) = P(A) + P(B) - P(A&B)

                    P (A U B ) = 0.23 + 0.76 - 0.1995

                    P (A U B ) = 0.7905

- c) P ( A / B )?

                    P ( A / B ) = P(A&B) / P(B)

                                    = 0.1995 / 0.76

                                    = 0.2625

- d) P( B / A') ?

                   P( B / A') = P ( B & A') / P(A')

                   P ( B & A' ) = 1 - P( A / B) = 1 - 0.85 = 0.15

                   P ( B / A' ) = 0.15 / (1 - 0.23)

                                    = 0.194805

- e) Are the mutually exclusive ?

        The condition for mutually exclusive events is as follows:

                    P ( A & B ) = 0 for mutually exclusive events.

        In our case P ( A & B ) = 0.1995 is not zero.

        Hence, NOT MUTUALLY EXCLUSIVE

- f) Are the two events independent?

         The condition for independent events is as follows:

                    P ( A & B ) = P (A) * P(B) for mutually exclusive events.

        In our case,

                        0.1995 = 0.23*0.76

                        0.1995 = 0.1748 (NOT EQUAL)

        Hence, NOT INDEPENDENT

                     

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Using the <em>normal distribution and the central limit theorem</em>, we have that:

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<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

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The mean and the standard error are given by:

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Item b:

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Z = \frac{X - \mu}{s}

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The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

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Z = -2.07

Z = -2.07 has a p-value of 0.0192.

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There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

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