Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30
Factors of 50 = 1, 2, 5, 10, 25, 50
Factors of 100 = 1, 2, 4, 5, 10, 20, 25, 50, 100
common factors are: 1, 2, 5, 10
Hope that helps :D
Answer:
Step-by-step explanation:
hope this helps.
$1.25 & $10.25
Let c be the cost of renting one chair and t be the cost of renting table. We're given two equations:
#1. 5c + 3t = 37
#2. 2c + 6t =64
We have a system of equations. Using our system of equations calculator, we can solve this problem any of 3 ways below:
The real solutions are -5, -4, 4, 5. There are no complex solutions.
The equation ...
... x^4 -41x^2 +400 = 0
can be factored as ...
... (x^2 -16)(x^2 -25) = 0
... (x -4)(x +4)(x -5)(x +5) = 0
So, all roots are real and are ...
... x ∈ {-5, -4, 4, 5}
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These are the values of x that make the factors zero.
28
It is 8 combination 4- using a TI 84, type in 8, then hit math- over to probability then nCr- then 6
