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ANTONII [103]
3 years ago
13

Help me please with some of my math homework I don’t really understand what p is equal to

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

The value of p is 5.

<u>Step-by-step explanation</u>:

<u>step 1</u> : The given expression is -6( p -5 )

<u>step 2</u> : To find any unknown value in an expression, equate it to zero.

<u>step 3</u> : -6( p -5 ) = 0

<u>step 4</u> : Multiply -6 to each term in the bracket.

            -6p + 30 = 0

            -6p = -30

              p = -30/-6

              p = 5

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AfilCa [17]

Answer:

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4 0
3 years ago
Place values for 249.673
irakobra [83]
Hi! 

This question is worded a little funny, but i think in understand what it's asking. Forgive me if i'm wrong. 

Place values in math are pretty self-explanatory. It's just asking you what place each number is in.

For example:

If you were to write the number 12, the 1 would be in the tens place and the 2 would be in the ones place. 

When speaking about decimals, you pretty much just have to add the letters 'th' to the end of the place value, but instead of decreasing as the numbers grow smaller, you increase and the ones place doesn't exist. 

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3 0
3 years ago
i know what i entered are not the correct answers smh, someone please help w the correct answers!!! due today ;(
Oduvanchick [21]

Answer:

Ask your mom

Step-by-step explanation:

7 0
3 years ago
You are told that a third powered polynomial has zeroes at -1, 2, 5.
vichka [17]

Answer:

a) factors of polynomial are: (x+1)(x-2)(x-5)

b) the required polynomial in standard form is: \mathbf{x^3-6x^2+3x+10}

Step-by-step explanation:

The polynomial has zeros at -1,2,5

Part A) Write the three factors of the polynomial

we have x=-1, x=2 and x=5 as zeros of polynomial

so factors will be:

(x+1)=0, (x-2)=0, (x-5)=0

So, factors of polynomial are: (x+1)(x-2)(x-5)

Part B) Write the polynomial in standard form

For finding polynomial, we will multiply all the factors i.e

(x+1)(x-2)(x-5)

(x+1)(x-2)(x-5)\\=(x(x-2)+1(x-2))(x-5)\\=(x^2-2x+x-2)(x-5)\\=(x^2-x-2)(x-5)\\=x(x^2-x-2)-5(x^2-x-2)\\=x^3-x^2-2x-5x^2+5x+10\\=x^3-x^2-5x^2+5x-2x+10\\=x^3-6x^2+3x+10

So, the required polynomial in standard form is: x^3-6x^2+3x+10

7 0
3 years ago
Find a polynomial f(x) of degree 3 with real coefficents and following zeros. -4,4i
ElenaW [278]

Answer:

f(x)=x^3 +4x^2 +16x +64

Step by step explanation:

\text{Given that,  two roots are}~ -4~ \text{and}~  4i.\\\\\text{Let,}\\\\~~~~~~~x = 4i\\\\\implies  x^2 = 16i^2~~~~~~~;[\text{Square on both sides}]\\\\\implies x^2 = -16~~~~~~~~;[i^2 = -1]\\\\\implies x^2 +16 = 0\\\\\text{So,}~ x^2 +16~ \text{ is a factor of the 3 degree polynomial}.\\ \\ \text{The polynomial is ,}\\\\ f(x) = (x+4)(x^2 +16)\\\\~~~~~~~=x^3 +16x +4x^2 +64\\\\~~~~~~~=x^3 +4x^2 +16x +64

7 0
2 years ago
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