Answer:
Depth = 3 inches
Maximum cross-sectional area = 18 inches²
Step-by-step explanation:
Let 'D' be the depth of the gutter and 'W' be the width of the gutter, the cross-sectional area as function of depth, A(D), is:
The depth for which the derivate of the area function is zero is the depth that yields the maximum cross-sectional area:
The cross-sectional area for D = 3 is:
Answer:
{1,2,3,4}
Step-by-step explanation:
cant be zero, also got it right on edge 2020
Answer:
Step-by-step explanation:
x= - 4
That is a vertical line going through any point whose x value is - 4
Answer:
Anil runs more by 180m.
Step-by-step explanation:
Given that:
Length of side of square park = 90 m
We will find the perimeter.
Perimeter = 4s
Perimeter = 4(90) = 360 m
Measurements of rectangular parks = length 50 m and width 40 m
Perimeter = 2(Length + Width)
Perimeter = 2(50+40) = 2(90) = 180 m
360 m > 180m
Difference = 360 - 180 = 180 m
Hence,
Anil runs more by 180m.
Answer:
h=5
Step-by-step explanation:
18x2 = 36
36/6 = 6
6 = h+1
h=5
Check:
5+1 = 6
6x6 = 36
36/2 = 18
