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timama [110]
3 years ago
5

THE ANSWER IS NOT 12 OR 36 SO DO THE RSM ANSWER PLS ASAP PLS OH PLS 0-0 a * b=ba−ba+ab, find (2*3)×(3*2).

Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0

72 if * is exponents

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6. Find an exact value. (1 point)
vladimir2022 [97]
<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
sin 9x cos x - cos 9x sin x
</span>

sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

the answer is the letter c) sin 8x

<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
cos 112° cos 45° + sin 112° sin 45°

</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)

the answer is the letter d) cos 67°

10. Rewrite with only sin x and cos x.

sin 2x - cos 2x

 

sin2x = 2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>

sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2

sin2x- cos2x=2sinxcosx-1+2(sinx)^2

<span>the answer is the letter <span>b) 2 sin x cos2x - 1 + 2 sin2x</span></span>
4 0
3 years ago
Read 2 more answers
Can someone please help me on these two questions.
Valentin [98]
What are the questions
5 0
3 years ago
Write an equation of the circle with center (3, -6) and radius 5.
lesya692 [45]

Answer:

formula for a circle: (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center and r is the radius.

1. Plug in center coordinates into formula

(x-3)^2 + (y-(-6))^2 = r^2

2. Plug in radius value

(x-3)^2 + (y-(-6))^2 = 5^2

3. Simplify:

(x-3)^2 + (y+6)^2 = 25

3 0
3 years ago
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Solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the original logarithmic expressio
KIM [24]

Answer:

Therefore x=9

Step-by-step explanation:

Give that,

log x+ log (x-3) = log 54

log x(x-3) =log 54             [    log_ca+log_c b=log_c(ab)   ]

x(x-3) = 54

Now expand the above equation to get a quadratic equation

x²-3x=54

⇒x²-9x+6x-54=0

⇒x(x-9)+6(x-9)=0

⇒(x-9)(x+6)=0

⇒x-9=0  or, x+6=0

⇒x=9,-6

Now putting x= -6 in the given expression,

log(-6)+log(-6-9)=log 54.

Since log (-6) does not exist.

Therefore x=9

8 0
3 years ago
Find the volume of the cylinder.
VARVARA [1.3K]

Answer:

The answer to the test is 1. B 2.C 3.B 4.A and this is one is C for the answer.

4 0
3 years ago
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