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Vilka [71]
3 years ago
12

A parabola passes through (7,42) and has a vertex at (-2,6).

Mathematics
2 answers:
Serggg [28]3 years ago
5 0

Answer: To solve this you need to use the vertex form of the equation of a parabola which is y=a(x−h)2+k , where (h,k) are the coordinates of the vertex.

Step-by-step explanation:

Natali [406]3 years ago
3 0

Answer:

there is no "a" value for me to find

Step-by-step explanation:

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Factor completely. x^2-3x-28
Mars2501 [29]

Answer:

= (x+4) (x-7)

Step-by-step explanation:

x²-3x -28

Product = -28

Sum = -3

numbers = -7 and 4

Thus;

x²- 3x -28 ; replacing -3x with -7x and 4x

x²-7x +4x -28

x(x-7) + 4(x-7)

<u>= (x+4) (x-7) </u>

4 0
3 years ago
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HELP ASAP WITH MATH DECIMALS!!! I WILL UPROVE!!!
andriy [413]
Total time taken to attach the wheels and hood to a car = 8.216 + 3.652 = 11.868 seconds

Total time taken to attach good and wheels to 425 cars = 11.868 x 425 = 4925.22 seconds


Ans. 4925.22 seconds


8 0
3 years ago
A+ B = 30. A:B what is equivalent to 2:3
Paraphin [41]
2/3 and 12/18 are equivalent fractions, and 12+18 = 30 so the answer is 12:18 
5 0
3 years ago
What is the equation of a horizontal line passing through the point (-3, 8)?
djyliett [7]

Answer:

Y=8

Step-by-step explanation:

A horizontal line is going to be parallel to the x-axis, so you need to use your y-value to determine the equation of the line. Your y-value in the coordinate (-3,8) is 8, so y=8

5 0
3 years ago
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A rational number raised to a rational power can either be rational or irrational. For example, 4^( 1/ 2) is rational because 4
Lady bird [3.3K]

Answer:

Step-bThis is an interesting problem. To solve it I should find two irrational numbers r and s such that rs is rational.

I am not sure I am able to do that. However, I am confident that the following argument does solve the problem.

As we know, √2 is irrational. In particular, √2 is real and also positive. Then √2√2 is also real. Which means that it is either rational or irrational.

If it's rational, the problem is solved with r = √2 and s = √2.

Assume √2√2 is irrational. Let r = √2√2 and s = √2. Then rs = (√2√2)√2 = √2√22 = √22 = 2. Which is clearly rational.

Either way, we have a pair of irrational numbers r and s such that rs is rational. Or do we? If we do, which is that?

(There's an interesting related problem.)

Chris Reineke came up with an additional example. This one is more direct and constructive. Both log(4) and √10 are irrational. However

√10 log(4) = 10log(2) = 2.y-step explanation:

7 0
3 years ago
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