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3 years ago

A parabola passes through (7,42) and has a vertex at (-2,6).

2 answers:

5 0

Answer: To solve this you need to use the vertex form of the equation of a parabola which is y=a(x−h)2+k , where (h,k) are the coordinates of the vertex.

Step-by-step explanation:

Natali [406]3 years ago

3 0

Answer:

there is no "a" value for me to find

Step-by-step explanation:

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For the love of God help me !! I'm desperate for it tomorrow

USPshnik [31]

$D:5x-2>0 \wedge x>0 \wedge x-1>0\\D:5x>2 \wedge x>0 \wedge x>1\\D: x>\frac{2}{5} \wedge x>1\\D:x>1\\\log_2(5x-2)-\log_2x-\log_2(x-1)=2\\\log_2\frac{5x-2}{x(x-1)}=\log_24\\\frac{5x-2}{x(x-1)}=4\\4x(x-1)=5x-2\\4x^2-4x=5x-2\\4x^2-9x+2=0\\4x^2-x-8x+2=0\\x(4x-1)-2(4x-1)=0\\(x-2)(4x-1)=0\\x=2 \vee x=\frac{1}{4}\\\frac{1}{4}\not \in D \Rightarrow \boxed{x=2}$

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3 years ago

Read 2 more answers

Sanjay had a case of 24 bottles of water. In the first week Sanjay drank 3/8 of the bottles of water. In the second week Sanjay

Gnom [1K]

Answer:

The answer to your question is: 5 bottles

Step-by-step explanation:

Process

First week

Divide 24 by 8

24/8 = 3 bottles = 1/8

but Sanjay drank 3/8 = 9 bottles

And there are 24 - 9 bottles left = 15

- Second week

Divide 15 by 3

15/3 = 5 then 5 bottles = 1/3

but sanjay drank 2/3 = 10 bottles

Then, there are 15 - 10 bottles left = 5

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3 years ago

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

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3 years ago

Determine whether the following event is mutually exclusive or not mutually exclusive.

Softa [21]

Answer:

The event is mutually exclusive.

Step-by-step explanation:

Mutually exclusive events are events that cannot exist simultaneously.

Thus, events that are not mutually exclusive can exist simultaneously.

Since each student only has one major, a single student cannot be both a mathematics major and a business major.

So, the event is mutually exclusive.

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3 years ago

A cone had a diameter of 6 centimeters and a height that is 5 times the diameter. Using 3.14 for pi, which of the following can

marysya [2.9K]

Answer:

Step-by-step explanation:

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3 years ago