Answer:
the inter-quartile range will increase
Step-by-step explanation:
The initial data-set was;
20,32,32,45,50
Adding a new value 78 will have several effects;
The mean of the new set of values will increase since 78 is mostly likely to be an outlier.
The median of the new data set will increase. The median of the old data set is 32 while that of the new data set will be 38.5
The mode is the most frequent observation. Both the new and the old sets of values will have a mode of 32. The mode will therefore remain the same.
The inter-quartile range just like the range will increase
Answer:
Explanation:
Given:
The equation describing the forest wood biomass per hectare as a function of plantation age t is:
y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4
The equation that describes the annual growth in wood biomass is:
y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3
To find:
a) The year the annual growth achieved its highest possible value
b) when does y ′ (t) achieve its highest value?
a)
To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value


SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t
The year the annual growth achieved its highest possible value to the nearest whole number will be
year 4
b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.
Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4
The slope is 4/5
You would get the equation in y = mx + b form
m (slope) will be the coefficient of x
(0, 9) represents the y-intercept of the graph.
Since the slope is 1/3, this means that y will rise 1 for every 3 that x runs.
The points that can be used to make a line in this graph are (3, 10) and (6, 11).