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2 years ago

What is 80,000,000 +4,000,000+100+8 in standard form

Mathematics

2 answers:

____ [38]2 years ago

5 0

84,000,108 is in standard

dsp732 years ago

3 0

84,000,108
it answer have arrive

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I WILL MARK BRAINLIEST IF CORRECT! Click on the graph below to create a pentagon with vertices at the following points.

Andrei [34K]

Answer:

Looks good to me.

Step-by-step explanation:

Looks good to me.

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2 years ago

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bija089 [108]

125-45=M would be a simple way of writing the amount taken from the original

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3 years ago

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Jimmy's backyard is rectangle that is 18 5/6 yards long and 10 2/5 yards wide Jim buy sod in pieces that are 1 1/3 yard long and

g100num [7]

Answer:

111 pieces of soda

Step-by-step explanation:

step 1

Find the area of the rectangular backyard

The area of the rectangular backyard is equal to

$A=LW$

where

$L=18\frac{5}{6}\ yd=\frac{18*6+5}{6}=\frac{113}{6}\ yd$

$W=10\frac{2}{5}\ yd=\frac{10*5+2}{5}=\frac{52}{5}\ yd$

substitute

$A=(\frac{113}{6})(\frac{52}{5})$

$A=\frac{5,876}{30}\ yd^2$

step 2

Find the area of one piece of sod

The area of the rectangular piece of sod is

$A=LW$

where

$L=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd$

$W=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd$

substitute

$A=(\frac{4}{3})^2\\\\A=\frac{16}{9}\ yd^2$

step 3

Find the pieces of sod needed

To find out how many whole pieces of sod will Jim need to buy to cover his backyard, divide the area of the backyard by the area of one piece of soda

$\frac{5,876}{30} : \frac{16}{9}=\frac{52,884}{480}=110.175$

Round up

111 pieces of soda

8 0

3 years ago

Many companies "grade on a bell curve" to compare the performance of their managers and professional workers. This forces the us

GarryVolchara [31]

Answer:

option A

Step-by-step explanation:

given,

10% A grades 80% B grades 10% C grades

This year, managers with scores less than 35 received C's and those with scores above 425 received A's.

The mean has to be middle of two corresponding cutoff value

$\mu = \dfrac{35+425}{2}$

μ = 230

Cutoff Off C grade corresponds with the area of 0.10 is table A.

corresponding z- score according to Table A

Z = -1.28

now, standard deviation

$z = \dfrac{x-\mu}{\sigma}$

$\sigma= \dfrac{x-\mu}{z}$

$\sigma= \dfrac{35-230}{-1.28}$

σ = 152.3

Correct answer is option A

4 0

3 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago