I=U/R
As resistance goes up, current is goes down
Answer:



Explanation:
Given:
Length of the string, L = 1 m
Mass per unit length, (m/L) = 2.0 × 10⁻³ kg/m
Tension in the string, T = 80N
Now, We know that,
Frequency,
................(1)
where, V = velocity
also,

substituting the values in the equation we get

Now using the equation (1)

also,


Hence, the required frequencies are



Distance , d = a+b

The unit of d is in meter and t is in seconds.
So the unit of a a must be meter.
Now we have unit of b

is meter.
So unit of b*

= meter
Unit of b = meter/

So unit of a = m and unit of b = m/

.
The net charge of pantothenate is -1 whereas the net charge of phosphopantothenate is −2 in aqueous solution at pH 7.
<h3>What is the net charge of both pantothenate and phosphopantothenate?</h3>
At pH 7, the carboxylic acid of pantothenate will lose one hydrogen ion which leads to a net charge of −1 on pantothenate while on the other hand, the phosphate group of phosphopantothenate will lose two hydrogen ions (−2) so −2 charge appear on the phosphopantothenate.
So we can conclude that The net charge of pantothenate is -1 whereas the net charge of phosphopantothenate is −2 in aqueous solution at pH 7.
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