The solution would be like
this for this specific problem:<span>
KCL at Junction a. </span><span>
<span>+ I1 + I2 + I3 = 0 (1) </span>
<span>KVL
<span>+ 13 V - 0.2 R I1 - 0.025 R I1 - 5 V + 0.02 R I2 = 0 (2) </span>
<span>8 + 0.02 I2 = 0.225 I1 </span>
<span>I1 = 35.6 + 0.0889 I2 (2A) </span></span></span>
<span>KVL (bottom loop - CCW
direction) </span><span>
<span>- 0.02 R I2 + 5 V + 0.5 R I3 = 0 (3) </span>
<span>0.5 I3 = -5 + 0.02 I2 </span>
<span>I3 = -10 + 0.04 I2 (3A) </span></span>
<span>Replace
2A and 3A into 1. </span><span>
<span>+ I1 + I2 + I3 = 0 </span>
<span>( 35.6 + 0.0889 I2 ) + I2 + ( -10 + 0.04 I2 ) = 0 </span>
<span>1.129 I2 = -25.6 </span>
<span>I2 = -22.6A </span>
<span>Solve 2A and 3A for other currents. </span>
<span>I1 = 35.6 + 0.0889 I2 = 35.6 + 0.0889 * -22.6 = 33.5A </span>
<span>I3 = -10 + 0.04 I2 = -10 + 0.04 * -22.6 = -10.9A
So the answer is letter D.</span></span>
Answer:
F = 3.2 x 10⁻⁵ N
Explanation:
The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:
where,
F = gravitational force = ?
G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of object 1 = 235 kg
m₂ = mass of object 2 = 1.37 x 10¹² kg
r = distance between objects = 2.59 x 10⁴ m
Therefore,
<u>F = 3.2 x 10⁻⁵ N</u>
Answer:
a. Find the numerical value of the change of the electric potential energy
Explanation:
Answer:
Yeah, it can be diffracted. Though it depends on a diffracting medium.
It must have some magnetic fields .
Forexample; X-ray diffraction where electrons are diffracted to the target filament.
False....................................