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NNADVOKAT [17]
3 years ago
13

Which statement is not true about radiation

Physics
1 answer:
Mekhanik [1.2K]3 years ago
4 0
I don’t know i’m sorry
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The speed of light is 3.0 x 108 m/s. How far does light travel in one day? Remember that you should first convert the day into s
Anna35 [415]

Answer:

2.59\times 10^{13}\ m

Explanation:

The speed of light is 3.0 x 10⁸ m/s

We need to find the distance traveled by it in one day.

1 day = 24 hours

1 day = 24 × 3600 seconds

= 86400 s

Now, using the formula of speed to find the distance covered as follows :

d=v\times t

Putting all the values, we get :

d=3\times 10^8\ m/s\times 86400\ s\\\\d=2.59\times 10^{13}\ m

Hence, light will cover 2.59\times 10^{13}\ m of distance in one day.

6 0
3 years ago
Drag each tool to the correct category. Identify the common use of each tool used by space scientists and earth scientists
inysia [295]
<h3>Answer</h3>

Tools that magnify objects                   Tools that don't magnify objects

magnifying glass                                                  rule

telescope                                                            binoculars

microscope                                                    

   

<h3>Explanation</h3>

radio dish: is use to receive radio waves from the air.

binoculars: provide a magnified stereoscopic view of distant objects.

streak plate: is a technique which is used to grow bacteria on a growth media surface so that individual bacterial colonies are isolated and sampled.

wind vane: is used to determine wind direction.

ruler: is used for measuring a line.

microscope: is used to magnify the objects which are not visible by naked eyes.

magnifying glass: is used to magnifying tiny objects which are difficult to see yet they are visible.

telescope: use by space scientist to examine astronomical event that may take place in the sky which is too far.

8 0
3 years ago
Read 2 more answers
Los expertos de la industria dicen que los juegos están en camino de convertirse en el
ehidna [41]
Andaniol I’m for sure of it
6 0
3 years ago
A train is moving with a velocity of 20 m/s. when the brakes are applied the acceleration is reduced to -0.6 m/s².calculate the
Serhud [2]

Answer:

x = 333.33 [m]

Explanation:

To solve this problem we must use the following kinematics equation.

v_{f}^{2} = v_{i}^{2}-(2*a*x)

where:

Vf = final velocity = 0

Vi = initial velocity = 20 [m/s]

a = desacceleration = 0.6 [m/s^2]

x = distance [m]

Note: the final speed is zero as the body finishes its movement.

Now replacing:

0 = (20)^2 - (2*0.6*x)

1.2*x = 400

x = 333.33 [m]

3 0
3 years ago
A rocket-driven sled running on a straight level track is used to investigate the physiological effects of large accelerations o
Shtirlitz [24]

Answer:

A. a = 814.815 ft/s^2.

B. Distance, S = 320 ft.

Explanation:

Equations of motion

i. vf = vi + a*t

ii. S = vi*t + 1/2*(a*t)

iii. vf^2 = vi^2 + 2a*S

Given:

vi = 0 ft/s

vf = 1000 miles/hr

t = 1.8 s

g = 32 ft/ s2

Converting miles/hr to ft/s,

1 mile = 5280 ft

Also, 1 hr = 60 mins * 60s

= 3600 s

Therefore, 1000 miles/hr * 5280 ft/1 mile * 1 hr/3600 s

= 1466.7 ft/s.

A.

Using the i. Equation of motion,

1466.7 = 0 + a*1.8

a = 814.815 ft/s^2

Comparing a to g,

a = (814.815/32) * g

= 25.46 g

B.

Using the ii. Equation of motion,

S = 1/2 * (814.815) * (1.8)^2

= 1320 ft.

4 0
4 years ago
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