Question

Next you place the pan on a hot electric stove. While the stove is heating the pan, you use a beater to stir the water, doing 21471 J of work, and the temperature of the water and pan increases to 77.7°C. How much energy transfer due to a temperature difference was there from the stove into the system consisting of the water plus the pan?

Answer 1

Answer:

ΔQ =  11050.2 J

Explanation:

Assume mass of pan is 900 gm

Assuming mass of water is 100 gm

Assuming initial temperature of pan & water is Ti = 51.268 degree C

The final temperature is T_f = 77.7 degree C

The total energy required to raise temperature

$E = (m_{pan}c_{pan} + m_{water} c_{water}) \Delta T$

E = [(900)(0.9) + (100)(4.2)](26.44)

E = 32521.2 J

The energy transferred is given by

ΔQ = E-W

ΔQ = 32521.2 J - 21471 J

ΔQ =  11050.2 J