Next you place the pan on a hot electric stove. While the stove is heating the pan, you use a beater to stir the water, doing 21
1 answer:
Answer:
ΔQ = 11050.2 J
Explanation:
Assume mass of pan is 900 gm
Assuming mass of water is 100 gm
Assuming initial temperature of pan & water is Ti = 51.268 degree C
The final temperature is T_f = 77.7 degree C
The total energy required to raise temperature
E = [(900)(0.9) + (100)(4.2)](26.44)
E = 32521.2 J
The energy transferred is given by
ΔQ = E-W
ΔQ = 32521.2 J - 21471 J
ΔQ = 11050.2 J
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Answer:
120 volts is the root mean square (rms) average of the voltage as it varies with time.
Explanation:
A. The average voltage over many weeks of time (false)
Reason: Average AC voltage over one cycle is cycle (from one peak to other) is zero and so over many weeks of time it is zero.
B. The peak voltage from an AC wall receptacle (false)
Reason: The peak voltage of an AC source in North America is zero.
C. The arithmetic mean of the voltage as it varies with time (false)
Reason: Arithmetic mean AC voltage over one cycle is cycle (from one peak to other) is zero and so over many weeks of time it is zero.
D. One-half the peak voltage (false)
Peak voltage =170 Volts
One-half the peak voltage = 85 volts
E. The root mean square (rms) average of the voltage as it varies with time (True)
Reason:
The peak voltage and root mean square voltage are related by:
Average value of voltage over one cycle is zero, so instead of calculating average voltage for AC peak voltage is first squared and the mean is calculated.
Answer:
Explanation:
The process during which pressure remains constant is called an isobaric process.
Answer:
when volume and the number of particles are constant
Explanation:
Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
The ideal gas law is the equation PV = nRT
Where;
P is the pressure.
V is the volume.
n is the number of moles of substance.
R is the ideal gas constant.
T is the temperature.
Generally, raising the temperature of an ideal gas would increase its pressure when volume and the number of particles are constant.
This ultimately implies that, when volume and the number of particles are held constant, there would be a linear relationship between the temperature and pressure of a gas i.e temperature would be directly proportional to the pressure of the gas. Thus, an increase in the temperature of the gas would cause an increase in the pressure of the gas at constant volume and number of particles.